## A saturated mixture is heated, volume is doubled and pressure remains the same.

1. The problem statement, all variables and given/known data

A saturated water mixture is heated.

P1=200kPa
m=0.5kg
V1=0.3m^3
V2=0.6m^3

find
T1
T2
Internal Energy

2. The attempt at a solution

Using the pressure tables and interpolation I found T2=120.12

stuck on T2 and internal energy.
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 Quote by allly 2. The attempt at a solution Using the pressure tables and interpolation I found T2=120.12 stuck on T2 and internal energy.
Since you have the mass, for state 2, you can get the specific volume v2 by using v2=V2/m and read that off from the table.

Your table will also have values for specific internal energy, which when multiplied by mass, gives the internal energy.

 Tags isobaric, thermodynamics

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