Quiky question before my test tommorow morning

[EasyStyle4747]

quiky question before my test tommorow morning!

i can't believe i duno where to find out how to do this:

1) find intersections of the graphs:
x^2+y^2=41
x+2y=6

and

2)which of the following function is equivalent to the following piece function.

x-3, if x>=3
f(x)={
3-x, if x<3

a) g(x)=|x-3| b) g(x)=|x+3| c) g(x)=-|x-3| d)-|x+3| e) none of these

this is off like a study guide checklist for the test.

 

[recon]

1) find intersections of the graphs:
x^2+y^2=41
x+2y=6

Rearrange x + 2y = 6 to get x = 6 - 2y. Then plug this into x² + y² = 41. You get:

(6 - 2y)² + y² - 41 = 0

 

[M98Ranger]

Hi there,

I understand that you have a quick question before your test tomorrow morning. It sounds like you are struggling with some math problems. I would suggest reviewing your notes and practicing similar problems to prepare for your test.

For the first question, you can find the intersection of the two graphs by solving the system of equations. You can do this by substitution or elimination method. I would suggest looking at some examples and practicing similar problems to understand the concept better.

For the second question, the equivalent function is g(x)=|x-3|, option a). This is because the piecewise function given is equal to the absolute value of x-3, which is represented by the function g(x).

I hope this helps and good luck on your test tomorrow! Remember to stay calm and confident, and trust in your preparation. You got this!