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Fluid Mechanics: Bernoullis Theorem Demonstration?

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Andrew871
#1
Oct27-10, 08:59 AM
P: 1
Having trouble using the bernoulli equation to work out the dynamic head for this experiment.

the equation I am using is as follows:

P1/ρg+(v1^2)/2g+z1=P2/ρg+(v2^2)/2g+z2

Where:

P= static pressure
v = fluid velocity
z = vertical elevation of fluid so z1 = z2 for horizontal tube

so equation is now:

P1/ρg+(v1^2)/2g=P2/ρg+(v2^2)/2g

now the measurements taken for static presure head (h), in meter which is related to P using this realtionship:

h = P/ρg

which allows the bernoulli equation to be rewritten as:

h1+(v1^2)/2g=h2+(v2^2)/2g

now i am having trouble rearanging this part of the equation to work out the the dynamic head for the experiment
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