Calculate Third Force Direction and Magnitude | Forces and Velocity Problem Help

[dg_5021]

Problem-
An Object acted on by three forces moves with constant velocity. One force acting on the object is in the positive x direction and has a magnitude of 6.5N; a second force has a magnitude of 4.4N and points in the negative y direction. Find the direction and magnitude of the third force acting on the object.

answer-
(6.5^2 + 4.4^2)^1/2
=7.9N

Am having problems getting the answer for the direction. I used
Tan^- (4.4/6.5)= but I get .59507

and the answer in the back of the book is 34.1 for the direction. What am I doing wrong?please help

 

[Sirus]

Your calculator is in radians.:)

 

[dg_5021]

thanks for the help