## Young's modulus problem -- need a hint

There are two wires, one brass the other copper, both 50 cm long and 1.0 mm diameter. They are somehow connected to form a 1m length. A force is applied to both ends, resulting in a total length change of 0.5 mm. Given the respective young's moduluses of 1.3 x 10^11 and 1.0 x 10^11, I'm supposed to find the amount of length change in each section.

Apparently a variation of Hooke's law should be used here, such as F/A=Y(change in length/original length)

I'm stuck on how can I solve this with 2 unknowns (force and change in length)?
Regards
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 Quote by redshift There are two wires, one brass the other copper, both 50 cm long and 1.0 mm diameter. They are somehow connected to form a 1m length. A force is applied to both ends, resulting in a total length change of 0.5 mm. Given the respective young's moduluses of 1.3 x 10^11 and 1.0 x 10^11, I'm supposed to find the amount of length change in each section. Apparently a variation of Hooke's law should be used here, such as F/A=Y(change in length/original length) I'm stuck on how can I solve this with 2 unknowns (force and change in length)? Regards
Hello redshift! I'm going to rewritte your problem in terms of stress $$\sigma$$ (Pa) and unitary deformation $$\epsilon=\frac{L-L_o}{L_o}$$ where Lo is the original lenght. So that, the stress exerted is the same in each section of the wire:

Hooke's law: $$\sigma=E_t \epsilon_t=E_1 \epsilon_1=E_2 \epsilon_2$$ where "Et" (N/m^2) is the apparent Young modulus of the complete wire.

Compatibility of deformations: $$\bigtriangleup L=\bigtriangleup L_1 + \bigtriangleup L_2$$

Then, you have three equations for three unknowns: Et, epsilon1 and epsilon2.