
#1
Sep2504, 12:14 PM

P: 53

There are two wires, one brass the other copper, both 50 cm long and 1.0 mm diameter. They are somehow connected to form a 1m length. A force is applied to both ends, resulting in a total length change of 0.5 mm. Given the respective young's moduluses of 1.3 x 10^11 and 1.0 x 10^11, I'm supposed to find the amount of length change in each section.
Apparently a variation of Hooke's law should be used here, such as F/A=Y(change in length/original length) I'm stuck on how can I solve this with 2 unknowns (force and change in length)? Regards 



#2
Sep2504, 12:54 PM

Sci Advisor
PF Gold
P: 1,481

Hooke's law: [tex] \sigma=E_t \epsilon_t=E_1 \epsilon_1=E_2 \epsilon_2[/tex] where "Et" (N/m^2) is the apparent Young modulus of the complete wire. Compatibility of deformations: [tex]\bigtriangleup L=\bigtriangleup L_1 + \bigtriangleup L_2[/tex] Then, you have three equations for three unknowns: Et, epsilon1 and epsilon2. Hope this help you a bit. You've got two unknowns for 



#3
Sep2604, 12:33 AM

P: 53

I think I get it. Based on your equations, the ratio of the young's moduluses should equal the ratio of the individual increases, that is, 13/10 = L1/L2
Therefore, 10L1 = 13L2 Since, L1 = L2 = 0.5, then L1 = 0.5  L2. Plugging this into the above gives 10(0.5  L2) = 13L2, so that the increase of L2 (brass wire) is 0.21 mm. Many thanks! 


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