Why Are My Physics Calculations on Force and Acceleration Incorrect?

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Homework Help Overview

The discussion revolves around calculations involving force and acceleration on an inclined plane, specifically addressing two scenarios with different masses and forces applied. Participants are examining the correctness of their calculations and the underlying physics principles.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of free-body diagrams and vector components to analyze forces acting on the masses. Questions arise regarding the application of Newton's second law and the calculation of net forces.

Discussion Status

Some participants are exploring the assumptions made in the calculations, particularly regarding the direction of forces and the setup of the free-body diagrams. There is an ongoing examination of the methods used to derive acceleration and distance, with no explicit consensus on the correctness of the initial calculations.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the sharing of complete solutions. There is a focus on understanding the physics concepts rather than arriving at final answers.

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1) A mass 1.3 kilograms is pushed with a horizontal force 17.5 Newtons of a smooth inclined plane which bears an angle 12.5 to the horizontal. Find the acceleration of the mass (g = 9.81 m/s).

I got 2.12, but it was wrong, and I don't know why.

2) A mass 1.9 kilograms is pushed with a horizontal force 20 Newtons of a smooth inclined plane which bears an angle 27 to the horizontal. Find the distance the block moves in 6.5 seconds (g= 9.81 m/s2).

I got 198.13, but it was wrong, and I don't know why.
 
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1) What did you do to find that answer? (free-body diagram?)
2) Same approach as #1, so let's talk about that one first.
 
yes, i used a free body diagram.

For the first problem, I used a = (mg) sin12.5 /1.3kg and got 2.12.

For the second problem, what I did was I use vectors to find the x and y components. solve: x components = 1.9a and got a = 9.379. then I plug in a for x=vt + (1-2) (9.379) (6.5 squared) and got 198.13 meters.

What am I doing wrong?
 
For 1), I'm assuming you meant horizontal force 17.5 N up the incline. If I understand the problem correctly, 17.5 N is the applied force. In order to find acceleration in [itex]F_{net}=ma[/itex], you need to find the net force acting on the mass. Therefore, form your freebody diagram, re-arrange the vectors for normal force and gravitational force to find their sum (opposite direction than the applied force). From there, you should be able to find net force, and thus acceleration. I got 11.3 m/s^2 -- is that right?
 
That is why we ask people not to post the same thing in multiple locations. Post once, if it's in the wrong place it will get moved to the right one.
 

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