Calculating Velocity of Free Falling Objects | Bridge Experiment

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SUMMARY

The discussion focuses on calculating the final and average velocities of two free-falling objects: a stone thrown downward and a pebble thrown upward from a height of 20.0 meters. The stone is thrown with an initial velocity of 12.0 m/s, and the effects of air resistance are ignored. For the stone, the final velocity upon reaching the water is calculated using the kinematic equation V_f^2 = V_i^2 + 2a(X_f - X_i), where a is 9.80 m/s². The average velocity for both objects is determined by the formula for average velocity as the change in position over the change in time.

PREREQUISITES
  • Understanding of kinematic equations, specifically V_f^2 = V_i^2 + 2a(X_f - X_i)
  • Knowledge of average velocity calculation: change in position over change in time
  • Familiarity with the concept of free fall and gravitational acceleration (9.80 m/s²)
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the application of kinematic equations in various motion scenarios
  • Learn about the effects of air resistance on free-falling objects
  • Explore the concept of projectile motion and its equations
  • Investigate real-world applications of free fall in physics experiments
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Students studying physics, educators teaching kinematics, and anyone interested in understanding the principles of free fall and motion calculations.

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***free Falling Objects ***

*FREE FALLING OBJECTS*

Q. A boy stands at the edge of a bridge 20.0 m above a river
and throws a stone straight down with a speed of 12.0 m/s.
He throws another pebble straight upward with the same
speed so that it misses the edge of the bridge on the way
back down and falls into the river. For each stone find (a)
the velocity as it reaches the water and (b) the average
velocity while it is in flight.

Note: Ignore the affects of air resistance.
there's SO MANY FORMULAS FOR VELOCITY WHICH ONE AM I SUPPOSE TO USE? PLEASE HELP :cry:
 
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Faiza said:
*FREE FALLING OBJECTS*

Q. A boy stands at the edge of a bridge 20.0 m above a river
and throws a stone straight down with a speed of 12.0 m/s.
He throws another pebble straight upward with the same
speed so that it misses the edge of the bridge on the way
back down and falls into the river. For each stone find (a)
the velocity as it reaches the water and (b) the average
velocity while it is in flight.

Note: Ignore the affects of air resistance.
THERES SO MANY FORMULAS FOR VELOCITY WHICH ONE AM I SUPPOSE TO USE? PLEASE HELP :cry:
Alright what quantities do we have?
a, x, v_i... What are we solving for? v_f for part (a)
t for part (b)
Part (a)
ok, what relates a, x, v_i and v_f?
or perhaps I should say v_i^2 and v_f^2?... Hope that's not too obvious

ok part (b)
What relates a, t, x, and v_i?
I think you know the answer to this... hint it involves t^2 and t
Also what is the average velocity?
Wouldn't that be change in position over change in time?
 
Okay so for part a, V_xf^2 = V_xi^2 + 2a_x (X_f-X_i) is the kinematic equation that gives the velocity as a function of position, so a=9.80m/s^2 and Vi=12.0 m/s and x= 20 m for both pebbles?
 

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