
#1
Nov1910, 12:51 PM

HW Helper
P: 3,225

1. The problem statement, all variables and given/known data
This one seems pretty simple  that's exactly why I want to check it. One needs to show that if X has a countable dense subset, then every collection of disjoint open sets in X is countable. 3. The attempt at a solution Let U be a collection of disjoint open sets in X, and let A be a countable subset of X which is dense in X. Let Ui be any member of U. Then Ui contains an element of A, since if x is in Ui, x is either in A or a limit point of A. If x is a limit point of A, choose a basis element of the topology of X which contains x and is contained in Ui. Then this basis element intersects A in some point other than x. Hence, Ui contains an element of A. Since any two members of U are disjoint, they will contain different elements from A. This gives a onetoone correspondence between the countable set A and the family U, so U is countable. 


Register to reply 
Related Discussions  
Metrizable space with countable dense subset  Calculus & Beyond Homework  9  
Subset dense in R  Calculus & Beyond Homework  7  
every infinite set has a countable dense subset?  Calculus & Beyond Homework  6  
A metric space having a countable dense subset has a countable base.  Calculus & Beyond Homework  2  
infinite subset is dense  Introductory Physics Homework  11 