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Calculating Distance Using Force, Mass, and Acceleration 
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#1
Nov2410, 06:40 PM

P: 2

1. The problem statement, all variables and given/known data
A rock is dropped from x(meters) height. The rock weighs 68 kg, and its force at impact with the ground is 15 kilonewtons. If the acceleration due to gravity is 9.8m/s^2, what is the distance/height the rock has fallen? 2. Relevant equations F=m*a 15kN=15000kg*m/s^2 666.4N=68kg*9.8m/s^2 The force exerted by the rock at stationary position is 666.4 Newtons. The rock fall distance is x meters. 3. The attempt at a solution 666.4N*x=15000N (666.4kg*m/s^2)*x=15000kg*m/s^2 x=(15000kg*m/s^2)/(666.4kg*m/s^2) x=22.51 This was all I could come with, but it is simply the ratio of the force. How do I find distance? 


#2
Nov2510, 06:15 AM

Mentor
P: 41,325

Please state the complete problem exactly as given. As you've written it, there's not enough information. (The impact force depends on the nature of the surface being hit.)



#3
Nov2510, 03:59 PM

P: 153

I don't see elastic/inelastic collisions mentioned. 


#4
Nov2510, 05:02 PM

Mentor
P: 41,325

Calculating Distance Using Force, Mass, and Acceleration



#5
Nov2510, 07:28 PM

P: 2

The question may be better understood as follows: A person who weighs 68 kg falls an unknown distance. The climber's rope has a breaking strength of 15 kN, and a dynamic elongation of 29%. Barring any other variables (friction, etc.), what is the furthest distance the climber could fall before the rope fails? 


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