Proving the Existence of One Positive Integer m and n for x in Real Numbers

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Homework Help Overview

The discussion revolves around proving the existence of unique positive integers m and n for a given real number x, specifically that m satisfies m ≤ x < m + 1 and n satisfies n < x ≤ n + 1. The context is mathematical reasoning related to properties of real numbers and integers.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to establish a proof using the concepts of supremum and sets of integers related to x. Some participants question how to approach the proof without providing direct solutions.

Discussion Status

Participants are engaging in a dialogue about the proof's requirements and structure. Some guidance has been offered regarding the use of supremum in defining m and n, but there is no explicit consensus on the proof's details or completeness.

Contextual Notes

There is an emphasis on adhering to forum rules regarding homework help, indicating that participants are encouraged to assist in understanding rather than providing direct answers. The original poster's repeated request suggests a need for clarification on the proof process.

YourLooks
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x is a real number, could you tell me how to prove that there will always be one and only one positive integer m such that m=< x <m+1 and one and only one positive integer n such that n< x =< n+1 ?
Thank you...
 
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Looks like homework, read the rules on homework above (we'll help you, but we won't do it for you).
 
Oh, Poet jcsd, I didn't know that.
But how will Poet help me ?
 
YourLooks said:
x is a real number, could you tell me how to prove that there will always be one and only one positive integer m such that m=< x <m+1 and one and only one positive integer n such that n< x =< n+1 ?
Thank you...
Suppose there are 2 sets X and Y, X={k belongs to Z : k<x}, Y={k belongs to Z : k<=x}, which means X and Y are not set zero and there should be a sup. Now you only need to let m=supX and n=supY then try to prove m belongs to X and n belongs to Y. Thats all.
 
Thank you for helping Yourlooks, you are really new to this forum :wink:
 

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