| New Reply |
Measurements and Operators |
Share Thread | Thread Tools |
| Dec2-10, 10:57 AM | #1 |
|
|
Measurements and Operators
I am trying to understand the idea of measurements on a system. Forgive me if any of my interpretations are incorrect...I'm hoping things can be cleared up.
A measurement is taken on a system, represented by an operator, and this measurement changes the state of the system into a state which corresponds to an eigenfunction of the operator. If a different measurement is then taken, and this operator commutes with the previous one, does that mean that both operators have the same eigenfunctions? I arrived at this because, if they commute, the order they are applied wont matter, so the state of the system should be the same???? Of course, if they dont commute, one measurement changes the state of the system so that the system is now different when one takes the second measurement, affecting its result. |
| Dec2-10, 02:08 PM | #2 |
|
|
yes if two operators commute they share the same eigenfunctions and can be measured at the same time with 100% certainty in both
|
| Dec3-10, 03:17 AM | #3 |
|
|
If two operators commute, then one can choose common eigenfunctions, but that does not mean that every eigenfunctions of A is an eigenfunction of B. Take for instance A=Identity operator.
|
| New Reply |
| Thread Tools | |
Similar Threads for: Measurements and Operators
|
||||
| Thread | Forum | Replies | ||
| Measurements in LQG | Beyond the Standard Model | 9 | ||
| Quantum Operators (or just operators in general) | Advanced Physics Homework | 22 | ||
| Measurements as operators | Advanced Physics Homework | 18 | ||
| Measurements in GR | General Physics | 0 | ||
| Measurements in GR | General Physics | 0 | ||