Help, about Fibonnaci Sequence / Golden Mean

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Homework Help Overview

The discussion revolves around the Fibonacci sequence and its relationship to the Golden Mean. The original poster seeks to understand the convergence of the ratios of successive Fibonacci numbers and how to determine a specific value of N for a given epsilon in the context of convergence.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find the limit for the Golden Mean using the Fibonacci sequence and expresses uncertainty about the convergence definition. Other participants inquire about the formula for the related sequence and suggest a potential formula for the Golden Mean.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the Fibonacci sequence and its convergence properties. Some hints have been provided, but there is no explicit consensus or resolution yet.

Contextual Notes

The original poster mentions a specific epsilon value for convergence, indicating a focus on formal definitions and calculations. There is also a question about the formula for the Golden Mean, suggesting potential confusion or differing interpretations among participants.

leoflc
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Fibonaci Sequence,
{1,1,2,3,4,8,13}
If you take successive ratios of these term, we generate a realted sequence,
{1/1, 1/2, 2/3, 3/5, 5/8, 8/13}
and this sequence converges to the Golden Mean. Using the formal definition of convergence, find the appropriate [itex]N[/itex] if [itex]\varepsilon = 0.0001[/itex]
------------------------------------------------------------------
I know Fibonnaci Sequence is [itex]a_n = a_{n-1} + a_{n+1}[/itex]
and I need to find the limit for the Golden Mean?

could anyone give me a hand?
Thank you very much!
 
Last edited:
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what is the formula of the related sequnce?
this is the sequence you are concerned with.
 
I'm still working on the formula for the Golden Mean, but is it [tex]\frac{(n-1)+(n-2)}{n+1}[/tex]
?
 
Hint:

[tex]\frac {a_{n+1}}{a_n} = 1 + \frac {a_{n-1}}{a_n}[/tex]
 

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