Different techniques of integration

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Homework Help Overview

The discussion revolves around different techniques of integration, specifically focusing on the integral of a rational function involving a polynomial in the numerator and a power of a binomial in the denominator.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the original poster's integration attempt and question the validity of the result. There are mentions of using different integration methods, including the tabular method and substitution. The original poster also seeks clarification on formatting mathematical expressions in LaTeX.

Discussion Status

The conversation is ongoing, with participants providing guidance on both the integration techniques and the formatting of mathematical expressions. Some participants have suggested alternative methods and are encouraging the original poster to share more details about their work to identify any mistakes.

Contextual Notes

There is a mention of using a graphing calculator to verify the results, indicating that the original poster may be working under constraints related to homework rules or expectations for checking work.

DennisG
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hi, we're working on different techniques of integration and I just wanted to know if I got the right answer for this...

[tex]\int\frac{x^3}{(x+1)^10} dx[/tex] (the denominator should be raised to the tenth and not the 1 with a big zero after it, if someone could tell me how to raise it to a power like that, it would also be appreciated)

I only got [tex]\frac{-(x+1)^-11}{11}\times\frac{x^4}{4}[/tex]

thanks
 
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First, I'll address the latex problem: x^{10} will display [itex]x^{10}[/itex]. Superscripting and subscripting should be surrounded by {}.

Next, what new method are you using? You can use the tabular method (a relative of integration by parts) and I'm sure there's at least one more method.

Another thing, if you have a graphing calculator you can check your answer by evaluating the indefinate integral as a definite integral--say 0 to 1 in this case. Evaluate your answer as a definite and see if the numbers you get from both methods are the same... I evaluated the original int from 0 to 1 and got a positive number and I see the bottom will yield a negativeover the same limits, so your answer is wrong. If you show us what you've done then someone will be able to point out your mistake.

Anyway, good luck.
 
DennisG

Try this

[tex]u = x+1[/tex]

so

[tex](u-1)^3 = x^3[/tex]

Do you see it now?
 
ohhhhhh
thanks a lot
 

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