Register to reply

Nuclear medicine, total energy, dose in rem

Share this thread:
Dec3-10, 05:06 PM
P: 3
I cant seem to get this started in the right direction. Any help is appreciated.

As part of a treatment program, a patient ingests a radioactive pharmaceutical containing P32,15, which emits beta rays with an of 1.50. The half-life of is 14.28 , and the initial activity of the medication is 1.34 .

Part A
How many electrons are emitted over the period of 7.00 days?

Part B
If the rays have an energy of 705 keV , what is the total amount of energy absorbed by the patient's body in 7.00 ?

Part C
Find the absorbed dosage in rem, assuming the radiation is absorbed by 110 grams of tissue.

First I converted all times to seconds.

T 1/2 = 1.234e6 s
t = 7 days = 604800 s

Converted activity (RO) into decays per second = 1.34e6

Found N from A-Z = 17

Found decay constant (lambda) = ln(2)/T 1/2 = 5.617e-7

Equations I have tried with no success are N=Noe^-(lambda)(t)
Phys.Org News Partner Science news on
New type of solar concentrator desn't block the view
Researchers demonstrate ultra low-field nuclear magnetic resonance using Earth's magnetic field
Asian inventions dominate energy storage systems

Register to reply

Related Discussions
Dosage and total Energy from radioactive medicine. High Energy, Nuclear, Particle Physics 1
Nuclear Model - Expression for Total Energy [Modern Physics] Introductory Physics Homework 2
Nuclear Medicine Medical Sciences 12
Absorbed dose of nuclear radioactivity Introductory Physics Homework 4