Register to reply 
Nuclear medicine, total energy, dose in rem 
Share this thread: 
#1
Dec310, 05:06 PM

P: 3

I cant seem to get this started in the right direction. Any help is appreciated.
As part of a treatment program, a patient ingests a radioactive pharmaceutical containing P32,15, which emits beta rays with an of 1.50. The halflife of is 14.28 , and the initial activity of the medication is 1.34 . Part A How many electrons are emitted over the period of 7.00 days? Part B If the rays have an energy of 705 keV , what is the total amount of energy absorbed by the patient's body in 7.00 ? Part C Find the absorbed dosage in rem, assuming the radiation is absorbed by 110 grams of tissue. First I converted all times to seconds. T 1/2 = 1.234e6 s t = 7 days = 604800 s Converted activity (RO) into decays per second = 1.34e6 Found N from AZ = 17 Found decay constant (lambda) = ln(2)/T 1/2 = 5.617e7 Equations I have tried with no success are N=Noe^(lambda)(t) 


Register to reply 
Related Discussions  
Dosage and total Energy from radioactive medicine.  High Energy, Nuclear, Particle Physics  1  
Nuclear Model  Expression for Total Energy [Modern Physics]  Introductory Physics Homework  2  
Nuclear Medicine  Medical Sciences  12  
Absorbed dose of nuclear radioactivity  Introductory Physics Homework  4 