How Do I Solve These Tricky Integration Problems?

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SUMMARY

The discussion focuses on solving two integration problems involving algebraic manipulation and trigonometric substitution. The first integral, ∫ (x-1)/√(4x²-1) dx, can be simplified by splitting it into two parts: ∫ x/√(4x²-1) dx - ∫ 1/√(4x²-1) dx. The second integral, ∫ 1/√(1+8x-4x²) dx, requires completing the square to transform it into ∫ 1/√(5-4(x-1)²) dx, followed by the substitution u = x - 1. These techniques are essential for tackling complex integration problems.

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  • Understanding of basic integration techniques
  • Familiarity with trigonometric substitution
  • Knowledge of algebraic manipulation for integrals
  • Ability to complete the square in quadratic expressions
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  • Explore trigonometric identities for integration, focusing on substitutions
  • Learn about completing the square in various contexts, particularly in calculus
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I am having problem with two math questions that I have been asked to try and although I do not need to do them they are really frustrating me.

First off intergrate (x-1)/squareroot(4x^2-1)

I am sure this is something to do with replacing x to get cos^2 (x)-1 so that this becomes 2cos(2x) but I can't intergrate from there either.

Also intergrate 1/squareroot(1+8x-4x^2) again I am sure it is a substitution for trig but I just can't see it.

Any help would be greatly appreciated. Sorry I caan't lay the questions out any better
 
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I'm sorry to say but for problems like this simple trig substations will not service, a bit of algebraic manipulation to make things look nicer is in order:

For the 1st one you should realize that:

[tex]\int \frac{x-1}{\sqrt{4x^2-1}} dx = \int \frac{x}{\sqrt{4x^2-1}} - \frac{1}{\sqrt{4x^2-1}}dx[/tex]

Now if you split the integral up:

[tex]\int \frac{x}{\sqrt{4x^2-1}}dx - \int\frac{1}{\sqrt{4x^2-1}}dx[/tex]

Not wanting to do the whole thing for you I'll leave you to work out the rest.

As for the second the trick I believe is completing the square:

[tex]\int \frac{1}{\sqrt{1+8x-4x^2}} dx= \int \frac{1}{\sqrt{5-4(x - 1)^2}}dx[/tex]

Then use the substation u = x - 1 and again I'll leave you to do the rest. (I would seriously check my arithmetic if I were you, not feeling that well on it tonight).
 
thanks

thank you for the quick responce. I can not believe I missed I really hate it when I overlook the obvious.

Thanks
 

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