Hey physics instant velocity ques

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Homework Help Overview

The discussion revolves around calculating the instantaneous velocity of an arrow shot upward on the moon, described by the height function h=58t-0.83t^2. The original poster seeks clarification on how to find the instantaneous velocity after one second without using derivatives, as this is for a calculus class where derivatives are not permitted.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of instantaneous velocity and its relation to derivatives. Some suggest using a table of values to find average velocities, while others propose graphing the function to estimate the slope at a specific point.

Discussion Status

The conversation is ongoing, with participants exploring different methods to approach the problem. Some guidance has been offered regarding the use of slopes and graphing, but there is no explicit consensus on how to proceed without derivatives.

Contextual Notes

The original poster mentions restrictions on using derivatives for their homework, which adds complexity to the discussion. There is also an indication of confusion regarding the application of the concepts discussed.

lilman7769
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If an arrow is shot upward on the moon with a velocity of 58m/s, its height in meters after t seconds is given by h=58t-0.83t^2

find the instantaneous velocity after one second...can u post ur work?? and explain this to me...thx in advance...
 
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Instant Velocity is

[tex]\vec{V} = \frac{d \vec{r}}{dt}[/tex]

If you have this formula, then the first derivative is speed. For velocity, remember to put the j, because it's 1D motion in the y-axis.

[tex]h=58t-0.83t^2[/tex]
 
its for a calculus class and we arent allowed to use derivtives yet...so for that forula u gave me what number would i plug in? I am kinda confused...i did a table of values with time intervals to average velocity but the whole one second i don't understand...can u show me like an answer...im sorry ur rules are u not doing my hmk...i seriously have tried i just don't understand...
 
You could graph that function, and pick really close values for time and h, to calculate the slope.

The First derivative is the slope.

Slope formula
[tex]m = \frac{\Delta h}{\Delta t}[/tex]
 

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