Calculating Net Force: 11.3N Bucket Pulled by 8.7N & Unknown Angle Force

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Homework Help Overview

The discussion revolves around calculating the net force acting on a bucket of water, which weighs 11.3 Newtons, being pulled by two forces: one of 8.7 Newtons at an angle of 51 degrees from the vertical, and a second force at an angle of 15 degrees from the vertical. The original poster seeks to determine the magnitude of the second force given only its angle.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster questions how to find the magnitude of the second force with limited information. Some participants suggest drawing a free-body diagram to visualize the forces acting on the bucket. Others hint at the relationship between the horizontal components of the forces, implying a balance is necessary for a purely vertical net force.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some guidance has been offered regarding the use of a free-body diagram and the relationship between the forces, but no consensus or resolution has been reached.

Contextual Notes

There is a mention of a potential overlap with another question posted in a different forum, which may indicate a broader context or confusion regarding the problem.

buffgilville
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A bucket of water which weighs 11.3 Newtons is pulled vertically using two forces. The first of magnitude 8.7 Newtons acts at an angle 51 degrees from the vertical. The second acts at an angle 15 degrees from the vertical. Find the net force acting on the bucket (due to the forces and the weight) in Newtons.

How do I find the magnitude of the second when only the angle is given for it?
 
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Draw a freebody diagram on the body,

You know the forces acting on it Weight, and the other 2 forces.
 
Hint: If the net force is solely vertical, the two horizontal components of force had better be equal and opposite to each other.
 
Didn't you post the same question in the college level help ?

marlon
 

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