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Two cars head on at 50mphby AJ_2010
Tags: brick wall 
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#1
Dec1310, 03:44 AM

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Its probably been done previously but a search didn't return any results for me.
But anyway, Vehicle 'a' (Va) travels headon in to Vechicle 'b' (Vb). Both are travelling at 50mph. Both vehicles are identical in weight, tyre grip, transmission, general design, road surface etc. Is the impact speed 50mph or 100mph? The police and news reports always say 100mph. (Probably because higher number usually gets more attention from the viewer). But if you look at each vehicle in turn, each one is going through a transition of 50mph down to 0mph in the space of a crumple zone. So each vehicle is surely experiencing an impact speed of 50mph. Is it? But then, Va is 'receiving' the crash energy from Vb (and vice versa), so the energy absorption is higher than if either Va or Vb were to crash in to a stationary wall for example. So under this view could it be argued that the impact speed is indeed 100mph? (I suppose the term 'impact speed' is open to interpretation?) 


#2
Dec1310, 04:30 AM

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Hi AJ_2010!
But the simple answer is that if you use the frame of reference of either vehicle, the the other vehicle is approaching at 100 mph. 


#3
Dec1310, 06:06 AM

P: 25

tim  a shorter crumple zone assumes less impact speed no? Therefore acceleration (or experienced 'gforce') would be less?
Approaching at 100mph yes. I think this is why I mentioned at the end of my post that 'impact speed' probably needs interpretation. But the main point of my question is that I hear the police and news readers say 'impact speed' all the time. And they simply add up the speeds of the approaching vehicles. I was just wondering if this is actually misleading at all? 


#4
Dec1310, 06:17 AM

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Two cars head on at 50mph
ok, longer instead of shorter
no, it's the opposite of misleading, it's exactly the parameter that should be given … when you're about to be in a crash, it very much is your frame of reference that is the most relevant to finding what's about to happen to you! 


#5
Dec1310, 08:10 AM

P: 25

But if I look at it this way: I am in car Va travelling at 50mph and Vb hit us at 50mph. The car I am in comes to a stop from 50mph to 0mph within a fraction of a second and within a larger* crumple zone. *compared to hitting a stationary wall. Is this the same as me travelling at 100mph and hitting a stationary wall? Whereby I decelerate from 100mph to 0mph within a crumple zone of whatever it is and within a time frame of whatever it is. As kinetic energy increases on the square of velocity there is MUCH more energy involved in the impact speed of a 100mph car hitting a wall than a 50mph hitting another 50mph car..is there not? I may be wrong as I have not done the actual calcs for this. :) The wording of 'impact speed' is assuming the car is having to stop from quoted speed to zero. In this case my line of thinking would be that a headon collision in this example should be an impact speed of 50mph and not 100mph. Happy to be proved wrong of course. :) 


#6
Dec1310, 08:24 AM

P: 5,632

but of course cars crumple differently than a wall so the nature of the deceleration would likely be different....If the wall were a perfect solid and experienced no deformation, for example, likely the single car would crumple a LOT more than if it were only 1/2 of a pair of cars crumpling..... it gets to the heart of the matter.....the momentum (mv) is equal to the force (F) of impact times the duration of the impact (T)....so as the duration (T) gets bigger for some momentum, the force (F) gets smaller....the resulting effects are dependent on both force and duration of the force.... If that isn't especially clear, think about the car not crashing but instead just rolling to a stop from normal friction...you'd hardly feel the small force inside but it would take a relatively long time for the car to come to a stop. And of course no energy, nor momentum, would be lost to deformation of the auto body.... The above logic is why you may see plastic barrels of sand on highways...the sand gives way gradually when impacted by a car and so extends the duration (T) of energy disippation reducing the impact (F) to passengers...if you just double the duration of impact, you cut the force in half. 


#7
Dec1310, 08:46 AM

P: 8

Since you're comparing to a wall, I think you need to take two cases into consideration rather than one.
1) You are moving at 50 mph and the wall is stationary. 2) You are moving at 50 mph and the wall is also moving at 50 mph. In which case would there be a stronger impact? The second case, and to make sense of it, if the wall was stationary in this second case, it'd be as if you were moving at 100 mph. 


#8
Dec1310, 08:54 AM

P: 25

Is the car going from 50mph to zero in both cases? Or in the moving wall situation  would the car be going from 50mph to 50mph? Or to add some 'spice' to these cases : an HGV travelling at 50mph hits headon a car travelling at 50mph. The car would most likely go from 50mph to 20mph (or whatever it happens to be). And the HGV would go from 50mph to 20mph (for example). In this case is the impact speed 100mph or the change in velocity of the car? ie.70mph (assuming you are sitting in the car) I thought I had it all in place in my head but the replies here have got me thinking harder :) 


#9
Dec1310, 09:03 AM

P: 8

Oh ok, after looking at Naty's post, I think that answers your question the best.
As another way to think about it (and I guess a direct answer to your question since it's from an mass x acceleration standpoint versus a momentum one), F = ma, where a = dv/dt, the change of velocity over change in time. You're correct about the change in velocity, but the length of time will be shorter for an impact where both cars are moving at 50 mph, resulting in a larger acceleration and a larger force. 


#10
Dec1310, 09:04 AM

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#11
Dec1310, 09:22 AM

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#12
Dec1310, 10:19 AM

P: 1,018

Each vehicle undergoes a 50mph deceleration over the distance of its own crumple zone. So, as far as the vehicle is concerned, it's exactly the same as if you hit a stationary, immovable wall at 50mph. 


#13
Dec1310, 10:45 AM

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It depends on what you want to compare it to.
Two 50mph vehicles head on are equivalent to 100mph vehicle hitting a stationary vehicle. From that perspective, collision speed is 100mph. But if you want to compare to collision into solid wall, a 50mph collision will do the same damage as two identical 50mph vehicles head on. Since vehicles that collide usually aren't close enough to identical, the second comparison tends to be flawed. The first holds regardless of vehicle masses. So that would probably make more sense. 


#14
Dec1310, 11:03 AM

P: 161

This cant be true as the two particles traveling at constant and equal velocities cant collide. 


#15
Dec1310, 01:03 PM

P: 8

In that example, the magnitudes of their velocity were the same, the signs (AKA directions) were different. 


#16
Dec1310, 02:08 PM

P: 1,041

The TV show about myths addressed this issue. Two cars identical going at 50 mph crashing head on will each receive an impact equal to a single car at 50 mph hitting an immovable wall. The crumple distance & forces on the driver were indeed measured and affirmed.
But the reaction time would be based on a relative speed of 100 mph. E.g., if you were not paying attention & suddenly realized you are headed towards a brick wall, then you hit the brakes. The relative speed is 50 mph between your car & the wall. But if another car is approaching at 50 mph, the relative speed is 100 mph, meaning you'll have less time to slow down before impact. It's not a simple cut & dried problem, but it has been proven that the damage to the car(s) & impact force on the occupants is equivalent for 2 cars at 50 mph vs. a car & immobile wall at 50 mph. A single car hitting an immobile wall at 100 mph incurs much greater crumple of the car body, & much greater forces on the occupants. This scenario is more dangerous. Make sense? Claude 


#17
Dec1310, 02:52 PM

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The crash is effectively at 50 mph, not 100 mph. Think of it in terms of energy. If you have one car hitting a wall at 50 mph, you have the energy from that one car (let's call it E), and it is dissipated by that one car (the wall is stationary). If you have two cars moving at 50 mph, they both have energy E, but the mass is also doubled, so you are dissipating twice the energy but with twice the mass.
You could look at it in terms of forces if you wanted as well... or momentum. No matter how you slice it, a head on crash with two cars going 50 mph is the same as hitting a wall at 50 mph assuming the cars have the same mass. This actually was tested on the Mythbusters and they got it wrong the first time, so they revisited it after all the fans complained and got it right the second time. http://www.youtube.com/watch?v=cJGIYLZZUg Apologies if the LaTeX is messed up. This site always acts so goofy when it translates it... 


#18
Dec1310, 03:08 PM

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Yes, if two cars at 50 mph simultaneously hit opposite sides of the same brick wall, then that's obviously the same as if the wall wasn't there.
Putting the wall back: if the wall doesn't move at all, the effect on one car of hitting it at 50 mph is the same as the effect (on that car) of two cars crashing headon each at 50mph. 


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