- #1
MaximumTaco
- 45
- 0
xy'' -(2x+1)y' + (x+1)y = (x ex)2
I know a solution - (x-1)e2x
Thus, y= ((x-1)e2x u(x))
Now, i know how to do the whole reduction of order thing, but when i find y' and y'' and substitute, the u(x) term doesn't cancel out so this doesn't work
(x2-x)u'' + (2x2-x+1)u' + x2u = x2
So, how do i approach this? Thanks.
I know a solution - (x-1)e2x
Thus, y= ((x-1)e2x u(x))
Now, i know how to do the whole reduction of order thing, but when i find y' and y'' and substitute, the u(x) term doesn't cancel out so this doesn't work
(x2-x)u'' + (2x2-x+1)u' + x2u = x2
So, how do i approach this? Thanks.