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construct compact set of R with countable limit points |
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| Oct7-04, 07:43 PM | #1 |
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construct compact set of R with countable limit points
Construct a compact set of real numbers whose limit points form a
countable set. |
| Oct7-04, 07:48 PM | #2 |
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Shouldn't a single point be enough?
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| Oct7-04, 08:04 PM | #3 |
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Note:
I may have forgotten the precise definition of "the limit point". You might instead look at a convergent sequence in R; that is a compact set, with one limit point. |
| Oct7-04, 10:07 PM | #4 |
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construct compact set of R with countable limit points
for example {(0, 1/n) : n=1,2,3,......} is compact but the only limit point is 0. Still I need countable limit points.
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| Oct7-04, 10:11 PM | #5 |
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Note: A single point has no limit point, since
a limit point of a set A is a point p such that for any neighborhood of p (ie Ball(p,r) , where p is the origin and r=radius can take any value >0) there exists a q≠p where q belongs in B(p,r) and q belongs to A. |
| Oct8-04, 03:55 AM | #6 |
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Recognitions:
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You can construct a set with one limit point. Now you can make one with two limit points, 3 limit points, indeed any number of limit points countable or otherwise.
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| Oct8-04, 04:58 AM | #7 |
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![]() Finite sets are countable. |
| Oct8-04, 06:51 AM | #8 |
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| Oct8-04, 09:35 AM | #9 |
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Taking A={0, 1/n + 1/m | n,m >=1 in N}. Thus the limit points are 1/n which are countable.
Since the set is closed and bouned then it is compact. (theorem) Or It can prove by definition that A is compact, which is what I did since I forgot to use the theorem above which would have made life easier :) |
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