hedlund
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Let y = x^p where p is a natural number. Is it true that
[tex]\frac{dx^n}{d^ny} = \frac{p!}{(p-n)!} \cdot x^{p-n}[/tex] with the restriction that we define [tex](-n)! \equiv \infty[/tex] for n=1,2,3... I found this formula and I believe that it is true if we define [tex](-n)![/tex] to equal [tex]\infty[/tex].
[tex]\frac{dx^n}{d^ny} = \frac{p!}{(p-n)!} \cdot x^{p-n}[/tex] with the restriction that we define [tex](-n)! \equiv \infty[/tex] for n=1,2,3... I found this formula and I believe that it is true if we define [tex](-n)![/tex] to equal [tex]\infty[/tex].