Forgotten Units: kg, m/s^2, cm^3, mL Explained

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Homework Help Overview

The discussion revolves around understanding various units of measurement in physics, specifically focusing on the relationships between units such as kilograms, meters per second squared, cubic centimeters, and milliliters. Participants express confusion about unit conversions and calculations involving these units.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the equivalence of units like (kg)(m/s^2) and Newtons, and question the validity of adding different units such as atmospheres and liters. There are attempts to clarify calculations involving pressure and volume, as well as unit conversions.

Discussion Status

The discussion is active, with participants sharing their calculations and questioning assumptions about unit conversions. Some guidance has been offered regarding the relationships between units, but there is no explicit consensus on the best approach to the problem at hand.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is a focus on ensuring units are consistent throughout calculations.

nemzy
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What does (kg)(m/s^2) = what unit?

also does 1 cm^3= 1 mL?

i forgot all these units stuff its really bugging up my mind
 
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(kg)(m/s^2) = Newton

1 cm^3= 1 mL Yes
 
ok, I am confused, I've been stuck on this problem for about an hour

So far i got this in my calculations:

(5.316 L*atm) / ( (211.68 kg*m/s^2)+(.0073m^2*atm))

the answer is suppose to be in meters, and from these units i have no idea how it is possible..anyone have any ideas?
 
Show your work, by the way, L is liters right?
 
oh yeah and 1 more question, if u add units, then what happens?

like for example, if u have 8 atm + 3 liters, will it become 11 (atm+liters)?
 
k here is my work:

the equation is this:

h=n*R*T/(m*g+Po*A)

n= 1.85 moles
R=gas constant
T= 350 K
A= .00730 m^2
m= 21.6 kg

and Po is atmospheric pressure (1 atm or 1.0135e5 kPa)
 
Absolutely Not!
 
I don't believe you can do that, look up atm basic units, i mean Newton is kg*m/s^2, what is atm equal to? and use the relation above cm^3 = mL, and see if you can follow from that. This problems can be solved by converting to the same types of units, and simple elimination of analogous units.
 
that last post was directed at the previous post...about adding units
 
  • #10
a Pascal is N/m^2, use that. Also 1 atm = 101325 pascal.
 
  • #11
ok, so i ended up with this:

5.315975 L*atm / (211.68 N +739.6725 m^2*Pa)

but i am stuck here, how can i cancel out further units? since the bottom is addition, i have no idea what to do from here...am i still allowed to convert the m^2 to liters and cance it out with the top, as well as the Pa with the atm on top?
 
  • #12
well, a pascal times m^2 is just Newtons!

so you have all Newtons on the bottom...then instead of using that gas constant...use the one that is J * mol^-1 * K^-1

then you have J / N...which is meters (change them to their base forms if you want to double check it :) )
 
  • #13
nicely done :smile:
 
  • #14
gas constant:

8.314 J * mol^-1 * K^-1

instead of

8.2057 L * atm * mol^-1 * K^-1

there are a few other forms of the gas constant too, but these are the most commonly used ones.
 
  • #15
thx! i finally got the right answer..this units are really bugging

does anyone know a website that has all these info?
 
  • #16
It should be on your textbook, if not try google.
 

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