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Rather simple bouncing ball problem... average acceleration

 
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Oct9-04, 02:40 PM   #1
 

Rather simple bouncing ball problem... average acceleration


I'm stuck on this rather simple problem...

A golf ball released from a height of 1.4 m above a concrete floor bounces back to a height of 1.2 m. If the ball is in contact with the floor for .62 ms what is the average acceleration of the ball whil ein contact with the floor.

I know that the two heights are given, h1 = 1.4, h2 = 1.2 and t = .00062 s for then the ball is in contact with the floor.

In order to find the avg acceleration, I need to use change in v over change in time.

I'm having a hard time figuring out the velocity of when the ball bounces back upto 1.2 m. Can anyone please help me figure out this problem?
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Oct9-04, 03:06 PM   #2
 
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Use energy conservation to find

[tex]v = \sqrt {2 g h}[/tex]

after the bounce.
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