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Force on Earth by the radiation pressure of Sun 
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#1
Jan3111, 01:23 PM

P: 9

1. The problem statement, all variables and given/known data
Estimate the force on Earth due to the pressure of the radiation on Earth by the Sun. (At Earth's orbit, the intensity of sunlight is 1.37 kW/m^2.) 2. Relevant equations Radiation Pressure=I/c Pressure=F/A Using SA of earth=510,072,000 km2 3. The attempt at a solution So I have been working at this problem for a while now and can't seem to get the correct answer. I found the radiation pressure to be 4.5667e6 N/m^2. I have since then tried taking this and multiplying it by the surface area of the earth in many different forms to no avail. What am I missing? I have tried these coefficients to Prad*SA, 1 (acting on whole surface), 1/2 (half the surface since sun is on one side), 1/(2sqr2) (thought possibly rms), 1/sqr2 (similar to before, just trying anything), and 1/(4sqr2), 1/4. My force for Prad*SA=2.329e9 N. 


#2
Jan3111, 01:54 PM

HW Helper
P: 3,394

Welcome to PF!
I agree with 4.5667e6 N/m^2. I'm puzzled with what area to use. The sun only shines on one side of the Earth at a time so you certainly wouldn't use the whole surface area. Half of it doesn't seem right either because the sun hits a good part of it at a very high angle, drastically reducing the intensity. I think taking the area to be πrē is the best first estimate because it counts all of the radiation hitting the Earth. Of course all this assumes that the radiation is absorbed rather than reflected. 


#3
Jan3111, 02:38 PM

P: 9

Thank you for welcoming me and thank you for the help, using just pi*r^2 worked. 5.823e8 N is the answer.



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