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Boundedness of quantum observables? |
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| Feb1-11, 10:10 AM | #1 |
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Boundedness of quantum observables?
I don't like the C^*-algebraic foundations of quantum mechnaics since it assumes that every observable must be bounded and self-adjoint.
But most physical observables are not bounded. This came up in another thread, from which I quote some context: The integral of F_12(x) with a real, smooth hat function of narrow support is - by conventional standards - an observable whose support is a bounded region of space-time, but has continuous spectrum, hence is not bounded, and therefore not observable according to your definition. |
| Feb1-11, 10:39 AM | #2 |
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Since P is unbounded, it can't be a member of the C*-algebra of operators that correspond to observables. But is that a problem? Can't we use P to construct bounded operators that correspond to more realistic measuring devices? P corresponds to a measuring device that puts the particle in a momentum eigenstate (a concept that has issues of its own), but the bounded operators constructed from P would correspond to (for example) measuring devices that only confine the value of the momentum to a specific interval. I admit that I haven't thought this through to the end. ![]() One thought that occurs to me is that maybe the C*-algebra stuff is the best way to define observables when we intend to use a Hilbert space, and something else (that includes unbounded operators) is the best way to define them when we intend to use a rigged Hilbert space. But that's another thing I don't fully understand yet. |
| Feb1-11, 11:02 AM | #3 |
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Most of physics is phrased in terms of differential equations involving unbounded observables. Most of physics become unexpressible or clumsy to express when phrased in terms of bounded operators only. No commutation relations, no continuity equation, no field equations, no Noether theorem.... Sounds strange and is against Occam's razor. So I think the right mathematical setting should be an inner product space on which all observables of interest are defined (this common domain exists in all applications I am aware of), and its closure in various topologies depending on what one wants to do on the technical level. |
| Feb1-11, 11:38 AM | #4 |
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Boundedness of quantum observables?
To be honest A. Neumaier, I don't really have a disagreement. My initial post in the other forum was perhaps a bit trite. The Algebraic approach takes the bounded self-adjoint observables to correspond to measuring equipment, not observables. Without playing silly language games, an observable is precisely what you stated, a self-adjoint operator.
So momentum is an observable and is represented by an unbounded self-adjoint operator. Machines which measure momentum are represented by bounded self-adjoint operators. This is a fundamental point which I carelessly glossed over. In Algebraic QFT, the C*-algebra is the algebra of observables in the sense of what can be observed by actual equipment, not in terms of what are physical quantities. The interesting thing is that the theory can be developed and that certain points become clearer when you formulate the theory this way. For example it clears up some points in QFT in curved spacetime and other areas, because it describes pure and mixed states in a more unified way. Of course there are many cases where it is more cumbersome, e.g. analysis of the stress-energy tensor, field equations, e.t.c. (By the way, the canonical commutation relations fail to make sense in four-dimensions. Something which is related to wave-function renormalisation.) |
| Feb1-11, 11:46 AM | #5 |
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I should also say that there is still disagreement what exactly the algebra of bounded observables in a region represents. All that is certain is that all the information in a QFT is contained in them. That is you can reconstruct the QFT from these objects. (Again that statement has caveats, since AQFT is more general than field theory and contains relativistic quantum systems which are not field theories.)
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| Feb1-11, 12:08 PM | #6 |
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I prefer to have the foundations free from allusion to measurement. The latter should be a derived many-particle process to be analyzed by the statistical mechanics of the equipment interacting with the observed system. But it seems to me that the relevant unbounded observables always have a common domain on which they are true linear self-mappings, so that one could work instead with the algebra of linear self-mappings of this domain. Resolvents and exponentials would then live in closures of dense subalgebras of this algebra under appropriate topologies. Do you know of any work in that direction? |
| Feb1-11, 12:44 PM | #7 |
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This only shifts the weight from "measurement" to "preparation", so the allusion to measurement is just as strong in the Hilbert space approach, but perhaps better hidden. And you know what, the self-adjoint operators on this Hilbert space are still going to correspond to equivalence classes of measuring devices.
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| Feb1-11, 01:47 PM | #8 |
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The idealization that goes into the interpretation used in your description is only a didactical trick to make definitions a bit easier to swallow. (How do you justify the C^*-algebra axiom ||A^*a||=||a||^2 from measurement??) In experimental physics, measurement is a very complex thing - far more complex than your ''definition'' suggests. To measure the distance between two galaxies, the mass of the top quark, or the Lamb shift - just to mention three basic examples - can never be captured by the idealistic measurement concept in your definition. In each case, one assembles a lot of auxiliary information and ultimately calculates the measurement result from a best fit of a model to the data. Clearly the theory must already be in place in order to do that. (We don't even know what a top quark should be whose mass we are measuring unless we have a theory that tell us this.) And the Lamb shift (one of the most famous real observables in the history of quantum mechanics) is not even an observable in your sense! We develop a theory that simply gives a precise formal meaning to the concepts physicists talk about. This is pure math, in case of geometry consisting of textbook linear algebra and analytic geometry. The identification with real life is done _after_ having the theory (though the theory and the nomenclature was _developed_ with the goal to enable this identification in a way consistent with tradition): For geometry, by declaring anything in real life resembling an ideal point, line, plane, circle, etc., to be a point, line, plane, circle, etc., if and only if it can be assigned in an approximate way (determined by the heuristics of traditional measurement protocols, whatever that is) the properties that the ideal point, line, plane, circle, etc., has, consistent to the assumed accuracy with the deductions from the theory. If the match is not good enough, we can explore whether an improvement can be obtained by modifying measurement protocols (devising more accurate instruments or more elaborate error-reducing calculation schemes, etc.) or by modifying the theory (to a non-Euclidean geometry, say, which uses the same concepts but assumes slightly different properties relating them. For quantum mechanics, by declaring anything in real life resembling an ideal photon, electron, atom, molecule, crystal, ideal gas, etc., to be a photon, electron, atom, molecule, crystal, ideal gas, etc., if and only if it can be assigned in an approximate way (determined by the heuristics of traditional measurement protocols, whatever that is) the properties that the ideal photon, electron, atom, molecule, crystal, ideal gas, etc., has, consistent to the assumed accuracy with the deductions from the theory. If the match is not good enough, we can explore whether an improvement can be obtained by modifying measurement protocols (devising more accurate instruments or more elaborate error-reducing calculation schemes, etc.) or by modifying the theory (to a hyper quantum mechanics, say, which uses the same concepts but assumes slightly different properties relating them. This identification process is fairly independent of the way measurements are done, as long as they are capable to produce the required accuracy for the matching. Then, having established informally that the theory is an appropriate model for the physical aspects of reality, one can study the measurement problem rigorously on this basis:One declares that a real instrument (in the sense of a complete experimental arrangement including the numerical postprocessing of raw results that gives the final result) performs a real measurement of an ideal quantity if modeling the real instrument as a macroscopic quantum system (with the properties assigned to it by statistical mechanics/thermodynamics) predicts raw measurements such that, in the model, the numerical postprocessing of raw results that gives the final result is in sufficient agreement with the value of the ideal quantity in the model. Thus measurement analysis is now a scientific activity like any other rather than a philosophical prerequisite for setting up a consistently interpreted quantum mechanics. |
| Feb1-11, 05:09 PM | #9 |
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It is a long standing conjecture that: [tex]D = D_{0}[/tex] However this is not proven. At one time it was a major goal of axiomatic quantum field theory. [tex]\phi(0,\b{x}) = \int{\delta\left( t \right)\phi(t,\b{x})} dt[/tex] You can see that this requires quite a non-singular distribution. The field has to be an operator not only after smearing with a test-function, but even after a smearing with a temporal delta function. Since the fields grow more singular with increasing dimension and are more singular with interactions (in path integral language the path measure is supported on more singular fields), estimates on 4D fields imply that the time zero fields do not exist. However the field [tex]\phi_{r}[/tex] given by [tex]\phi = Z\phi_{r}[/tex], where [tex]Z[/tex] is an infinite constant in vague terms (more precise terms available if you want them) does have a time-zero field. It is of course the wave-function renormalisation. |
| Feb2-11, 09:30 AM | #10 |
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| Feb3-11, 05:28 AM | #11 |
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For example [tex]\phi^{4}_{4}[/tex], the theory is poorly defined when written on Fock space with the Hamiltonian: [tex]\int{d^{3}x \frac{\pi_{0}^{2}}{Z} - Z \nabla \phi_{0} \cdot \nabla \phi_{0} + m^{2}\phi_{0}^{2}+ \lambda\phi_{0}^{4}}[/tex] Where [tex]\phi_{0}[/tex] is the free field. To make it well-defined one puts in a cutoff [tex]\kappa[/tex] and gives [tex]Z,m[/tex] and [tex]\lambda[/tex] dependence on the cutoff. (I know you know all this, I'm just setting things up) If done correctly one will find that the Hamiltonian and its ground state [tex]\Omega[/tex] no longer have divergences. However the Hamiltonian will no longer converge to an operator in Fock space and [tex]\Omega_{\kappa}[/tex] will no longer converge to an element of the Fock space. To resolve this problem, one moves to the algebra of operators and treats [tex]\Omega_{\kappa}[/tex] as a state on that operator algebra. [tex]\Omega_{\kappa}[/tex] will then have a limit as a state on the algebra, but the Hilbert space you can construct from [tex]\Omega_{\infty}[/tex] is disjoint from Fock space. In the new Hilbert space the true physical field [tex]\phi_{p}[/tex], will have a well-defined Hamiltonian given by: [tex]\int{d^{3}x : \pi_{p}^{2} - \nabla \phi_{p} \cdot \nabla \phi_{p} + m^{2}\phi_{p}^{2}+ \lambda\phi_{p}^{4} :}[/tex] ([tex]::[/tex] indicates Wick ordering with respect to the vacuum of this Hilbert space) This Hamiltonian acts on the correct Hilbert space with no divergences. However this field will possess no time-slice localisation and cannot obey the canonical commutation relations. The axiomatic field theory way of viewing this would be to say that the Hamiltonian defined as a function of the physical field on the correct Hilbert space, is finite and well defined. However we only know how to work with Fock space. So to obtain/construct the correct field and Hilbert space we must use a cutoff approximation on Fock space as a starting point and use renormalization to take the correct limit out of Fock space. The type of renormalizations required tell you something about the real theory. In the case of wavefunction renormalization, the fact that the Fock space approximation needs a cutoff diverging term in the kinetic piece indicates that the real Hilbert space is one which does not support the canonical commutation relations. |
| Feb3-11, 06:04 AM | #12 |
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TS Walhout, Similarity renormalization, Hamiltonian flow equations, and Dyson's intermediate representation, Phys. Rev. D 59, 065009 (1999) http://arxiv.org/pdf/hep-th/9806097 But why this should follow rigorously was my question. It seems not to follow in dimension <4. But How can you give a rigorous argument in 4D when H hasn't even been constructed? |
| Feb3-11, 06:48 AM | #13 |
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For references Hepp is probably the best read if you can get it: Hepp K 1969 Theorie de la Renormalisation (Berlin: Springer) In their first monograph Glimm and Jaffe make some comments: Glimm J and Jaffe A 1972 Boson quantum field models London 1971, Mathematics of Contemporary Physics (London) pp 77–143 It's explicitly dealt with in: Zavialov O I and Sushko V N 1973 Statistical Physics and Quantum Field Theory ed N N Bogoliubov (Moscow: Nauka) You might find the papers of O Yu Shvedov interesting, he treats this stuff in the case of infinite discrete degrees of freedom. Not quite QFT, but half between QFT and QM. Makes some things clearer with out a lot of the technicalities. Also try any papers where they try to construct a 4D QFT, for example Schrader's. It was also first "discovered" very early on by the axiomatic field theory community unfortunately they never brought out a paper on it and the closest you'll get in early material is a brief reference in "PCT, Spin and Statistics, and all that" on page 101. I should say that the canonical commutation relations only fail in the sense of the formula they are usually expressed in. For example it is still true that: [tex] \left[\phi(x,t), \pi(y,s) \right] = D(x-y, t-s)[/tex] For some function [tex]D(x-y, t-s)[/tex]. It's just that [tex]D(x-y, t-s)[/tex] has singularities too strong when [tex] t \rightarrow s[/tex] that no Wightman field could satisfy the equation in that limit. |
| Feb3-11, 07:02 AM | #14 |
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| Feb3-11, 09:53 AM | #15 |
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there are various ongoing initiatives. . |
| Feb3-11, 10:19 AM | #16 |
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| Feb3-11, 10:58 AM | #17 |
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Have y'all considered that while an operator like X isn't bounded, other operators like arctan(X) are?
I really don't think you lose anything by laying the foundations via C*-algebras. Once you have a C*-algebra, you can use calculus (or other means) to construct additional algebras, if you so desire. |
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