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Gibbs Free Energy

by Chip90
Tags: energy, free, gibbs
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Chip90
#1
Feb2-11, 12:07 PM
P: 55
1. The problem statement, all variables and given/known data

You have two parts of a tank, divided by a divider. On the larger side, you have 4 mol of N2 gas and on the smaller side you have 1 mol O2 gas. Both gasses are are the same T and P. The divider is removed and the gasses mix.

What is the final T and P?

What is the change in Gibbs Free Energy


2. Relevant equations

Daltons Law of Partial Pressure



because T is constant

3. The attempt at a solution

So the final Temperature is the same as Ti because there is no chemical reaction

The final Pressure is the sum of the Pressures of Po + Pn = Pf
To solve this I just need Pf=2P ? (since each gas was at P pressure initially)

For the Gibbs free energy, the entropy changes, as well as pressure. But how do I solve this?

For the

Or do I use a different equal for that? The volume of the box doesn't change, so would I use ?
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