What does cross-sections perpendicular mean?

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SUMMARY

The discussion clarifies the concept of cross-sections perpendicular to a circular base in a solid volume problem. The base is a circle with a radius of 2, centered at the origin, described by the equation x² + y² = 4. Cross-sections perpendicular to the x-axis are squares, with their side length determined by the vertical distance from the top to the bottom of the circle, calculated as 2√(4 - x²). The area of each square cross-section is given by the formula 4(4 - x²).

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Allan
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I am having trouble understanding a question to a
volume problem.

The base of a solid S is a circle of radius two in the
xy plane centered at the origin. Cross-sections of
the solid perpendicular to the base are squares.

I am thinking y = 4-X^2. Where do I find the
shape for the squares? Can someone explain?
 
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The shape for the squares? Squares are squares!

I assume you mean the size of the squares.

To answer the title of you post, actually, saying "cross sections of the solid perpendicular to the base" is ambguous. The base is a circle of radius 2 centered at the origin (so x2+ y2 or y= +/-√(4- x2) (which is NOT quite what you have) . Imagine you have this object actually sitting in front of you. Take a sharp knife and slice through it. What you the cut side looks like (the cross section), depends on the angle the knife makes with the x and y axes as well as being perpendicular to the xy-plane.

I'm going to assume that cross-sections perpendicular to the x-axis are squares. (You hold your knife at right angles to the x-axis as you cut through the figure. The "cut end" looks like a square). A line through the figure, perpendicular to the x-axis runs from -√(4- x2) to +√(4- s2), a total length of 2&radic(4- x2). Being a square, the other sides are the same length and the area of the square is (2√(4-x2))2= 4(4-x2).
 
Thanks

I can see it now
 

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