# Homework check (too easy) with on/off design analysis for variable area turbojet

by roldy
Tags: analysis, check, design, homework, on or off, turbojet, variable
 P: 194 I'm studying on variable area turbojet problems in the book and I can't seem to get past this problem. Consider the performance of an ideal non-afterburning turbojet with flow at station 4(turbine entrance) and station 8 (nozzle throat) choked. A4 is fixed and A8 is varied in order to maintain constant compressor total pressure ratio ($$\pi_c$$). On-design conditions are as follows: $$\pi_{cR}=15, M_{oR}=2.0, \tau_{\lambda{R}}=7.0$$ Find the required ratio of nozzle throat area (off-design) to nozzle throat area (on-design) for the engine operating at the same flight Mach number (2.0) but at the off-design condition such that $$\tau_\lambda=6.0$$. My work: Using Mach number 2 On-design $$\tau_{rR}=0.8, \pi_{rR}=.458, \tau_{cR}=2.168, \tau_{tR}=.867, \pi_{tR}=.607$$ $$\tau_{tR}=1-\frac{\tau_{rR}}{\tau_{\lambda{R}}}(\tau_{cR}-1)=1-\frac{.8}{7}(2.168-1)=.867$$ Off-design Same values as on-design because Mach number does not change. $$\tau_{r}=0.8, \pi_{r}=.458, \tau_{c}=2.168, \tau_{t}=.867, \pi_{t}=.607$$ Using given $$\lambda=6$$ for off-design: $$\tau_t=1-\frac{\tau_r}{\tau_\lambda}(\tau_c-1)=1-\frac{.8}{6}(2.168-1)=.844$$ Hence, the area ratio: $$\frac{A_8}{A_{8R}}=\frac{\tau_t^\frac{1}{2}}{\pi_T}\frac{\pi_{tR}}{\tau _{tR}^\frac{1}{2}}=.9866.$$ Is this correct? This seems a little too easy.

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