Physics Problem Proof With Friend

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SUMMARY

The discussion centers on the correct formula for time (t) in a physics problem involving projectile motion. The participants debate whether the correct equation is t = √(2Vo²/g) or t = (Vo√2)/g. After analyzing the equations, they conclude that the professor's initial formula is incorrect due to unit inconsistencies. The correct formula, derived from the need to account for both ascent and descent, is confirmed as t = (2Vo√2)/(2g).

PREREQUISITES
  • Understanding of basic physics concepts, particularly projectile motion.
  • Familiarity with algebraic manipulation of equations.
  • Knowledge of gravitational acceleration (g) and its impact on motion.
  • Ability to interpret and analyze mathematical expressions in physics.
NEXT STEPS
  • Study the derivation of projectile motion equations in physics.
  • Learn about the implications of gravitational acceleration on time of flight.
  • Explore the differences between ascent and descent calculations in projectile motion.
  • Review common mistakes in physics problem-solving related to unit consistency.
USEFUL FOR

Students studying physics, educators teaching projectile motion, and anyone interested in understanding the mathematical foundations of motion under gravity.

Tom McCurdy
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We are trying to decide if this is true
we are trying to prove that t
equals

[tex]t= \sqrt{ \frac{2Vo^2}{g}}[/tex]
however we think the teacher may have misspoke and it should be
[tex]t= \frac{Vo\sqrt{2}}{g}[/tex]




[tex]Vosin45-gt=0[/tex]

[tex]Vosin45=gt[/tex]

[tex]t= \frac{Vosin45}{g}[/tex]

since you need to muliply by 2 since its only time up and you need time up and down

[tex]t= \frac{\frac{2V_0\sqrt{2}}{2}}{g}[/tex]

[tex]t= \frac{2V_0\sqrt{2}}{2g}[/tex]

[tex]t= \frac{Vo\sqrt{2}}{g}[/tex]
 
Last edited:
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As you may have noted, your prof.'s units don't add up, so his answer MUST be wrong!
 
YES! I am happy, I got yelled at by my friend when I suggested that he was wrong... we will see who is laughing at the end
 

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