Calculating the Radius of a Banked Curve Using Newton's Second Law

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Homework Help Overview

The discussion revolves around calculating the radius of a banked curve using Newton's second law. The scenario involves a car navigating a banked curve at a specified angle and speed, with the absence of friction being a key factor in the analysis.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the application of Newton's second law and the role of forces acting on the car, particularly the normal force and gravitational force components. Questions arise regarding the correct identification of forces contributing to centripetal acceleration and the setup of equations based on free body diagrams.

Discussion Status

Several participants provide insights into the force analysis, with some suggesting the need to consider the components of the normal force. There is an ongoing exploration of the relationships between the forces and the resulting equations, with participants attempting to derive the radius from their equations.

Contextual Notes

The problem is constrained by the conditions of a frictionless scenario and specific values for the angle and speed, which are central to the calculations being discussed.

mikep
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can someone please help me, i can't figure out where the angle on the free body diagram for this problem. i was thinking of using Newton's second law with a = v(squared)/R would this work?

A car goes around a curve on a road that is banked at an angle of 27.0°. Even though the road is slick, the car will stay on the road without any friction between its tires and the road when its speed is 23.0 m/s. What is the radius of the curve?
 
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Do the forces analysis and find which force component is working as the centripetal force.
 
well there is no friction force so the only thing pushing it to the center would be the acceleration, is that right?
 
Actually it will be a component of the normal force, try to draw all the forces on our particle, Normal and weight.
 
oh ok so
sumF = Ncosθ = m ((v^2)/R)

sumFy = Nsinθ - mg = 0

i used this and i solved for R = (v^2)/cotθ but i didn't get the correct answer. can you please tell me what i did wrong?
 
[tex]Ncos\theta = mg[/tex]

[tex]Nsin\theta = ma_{c}[/tex]

Look at the triangle...
 
oh i get it. its R = (v^2)/(tanθ g)
thank you for your help!
 

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