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Blade angles, Reaction, Diffusion |
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| Mar19-11, 05:44 PM | #1 |
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Blade angles, Reaction, Diffusion
I'm really confused about an in class example my professor did to show how to obtain the hub and tip degrees of reaction of a free-vortex compressor stage and the diffusion factor for the rotor tip
Given: [tex]\frac{\Delta P_t}{\rho {W_0}^2}=0.9[/tex] [tex]\frac{r_t}{r_h}=2.646[/tex] [tex]^{\circ}R_m=0.5[/tex] [tex]\sigma_m=1.0[/tex] [tex]\frac{\omega r_h}{W_0}=0.5[/tex] His results: [tex]D_{rotor,hub}=-.179[/tex] [tex]D_{rotor,tip}=0.56[/tex] [tex]D_{stator,hub}=.74[/tex] [tex]D_{stator,tip}=0.55[/tex] [tex]^{\circ}R_{tip}=0.714[/tex] [tex]^{\circ}R_{hub}=-1.0[/tex] The only values that I found where the [tex]^{\circ}R_{tip}[/tex] and [tex]^{\circ}R_{hub}[/tex]. For now, I'm just concentrating on figuring out the rotor tip diffusion. The equation that I have for the Diffusion of the rotor is as follows. [tex] D_{rotor}=1-\frac{cos(\beta_1)}{cos(\beta_2)}+\frac{1}{2\sigma}(tan(\beta_1)-tan(\beta_2))cos(\beta_1) [/tex] I would assume that the beta angles are the beta tip angles. This is where I got stumped. I don't have [tex]\omega[/tex] or [tex]W_0[\tex] to help me solve for the missing things. |
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