Register to reply 
Phasor Diagram RLC Series AC Circuit 
Share this thread: 
#1
Mar1911, 08:18 PM

P: 23

1. The problem statement, all variables and given/known data
I'm struggling to figure out what vectors I use for my phasor diagram for an RLC series circuit. 2. Relevant equations V_{C} = 1/j[tex]\omega[/tex]C V_{L} = j[tex]\omega[/tex]L V_{R} = IZ 3. The attempt at a solution I know how to add vectors, so that's not a problem, transfer my circuit from the time domain to frequency domain. I understand that V_{C} leads the current and V_{L} lags the current by [tex]pi/2[/tex] radians. If I have say, r[tex]\angle[/tex][tex]\theta[/tex] as my input voltage, then I can draw that on my phasor diagram because it is given to me as a vector (easy). In contrast, V_{C}, V_{L} and V_{R} are not vectors because after transferring them to the frequency domain, their unit is [tex]\Omega[/tex] which I think is a scalar quantity. My question is, how do I get a vector out of V_{C}, V_{L} and V_{R} in the frequency domain to plot onto my phasor diagram? 


#2
Mar2011, 02:06 AM

Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 11,868




#3
Mar2011, 08:00 AM

P: 23

Can you please check if I'm on the right track? It looks good to me. http://img585.imageshack.us/img585/117/55843578.jpg 


#4
Mar2011, 11:44 AM

Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 11,868

Phasor Diagram RLC Series AC Circuit
You've made several minor errors, but you're getting there. One error is that you left the factor of π out when calculating ω. Also, the sign of Z_{C} is incorrect. You can't just bring the j up from the denominator to the numerator. Finally, I'm not sure where you got X from, but the value you used for X is not consistent with your other calculations.
When you, for instance, calculate the voltage across the capacitor, don't write V=IR when you really mean V=IZ_{C}. It's sloppy and, from a mathematical perspective, plainly wrong. It's obvious what you mean, but it's the kind of thing that can annoy some instructors and graders. The more serious conceptual error is that you're not keeping track of the phases correctly. In the frequency domain, the voltages, the current, and the various impedances are all complex values, related by Ohm's Law: [tex]V = I Z[/tex] This equation concisely expresses the relationship between both the amplitude and phase of all the quantities. The equation [tex]V = I Z[/tex] is similar, but it only accounts for the amplitudes. In your calculations, the impedance you calculated is actually Z, not Z. So when you wrote that the current I is V with a phase divided by Z, that's not really correct. It's evidenced in the fact that if you add up the individual voltages you calculated, you'll find they don't add up to 12 V with phase of 0 degrees as it should. That's because the current I you calculated is missing the phase information. 


#5
Mar2011, 08:02 PM

P: 23

If I take the formula Z=[tex]\sqrt{R^2+X^2}[/tex], it appears strangely similar to the distance formula. Whereas X_{C} and X_{L} both have formulae 1/[tex]\omega[/tex]C and [tex]\omega[/tex]L respectively, yet they both have the unit of ohms. I've made some corrections, but now I have more errors :( With my new values for VC and VL, if I add them, they add to negative 12, which can't be right because I have a negative magnitude. http://img854.imageshack.us/img854/338/74199395.jpg 


#6
Mar2011, 10:32 PM

Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 11,868

The reactance X of an element is just its Z without the factor of j. The impedance of the circuit is
[tex]Z = Z_R + Z_L + Z_C = R + j\omega L  j\frac{1}{\omega C} = R + j\left(\omega L  \frac{1}{\omega C}\right)[/tex] Note Z is a complex quantity. If you find the modulus of Z, you get [tex]Z = \sqrt{R^2 + \left(\omega L  \frac{1}{\omega C}\right)^2}[/tex] The Z you calculated is actually Z. It doesn't contain phase information any more, which is why you got the puzzling results where everything had 0 phase. The current I you calculated is actually I. It's the amplitude with which the current oscillates. Similarly, you found V_{L} and V_{C}. (The minus sign for V_{C} indicates that V_{C} lags the current by 90 degrees.) To find the phase, what you want to do is draw the phasor diagram with V_{L}, V_{C}, and V_{R}. V_{L} and V_{C} are the lengths of two of the vectors. The vector sum of the three voltages then equals V of the source. 


#7
Mar2011, 11:16 PM

Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 11,868

To elaborate a bit more...
The voltage V, the current I, and the impedance Z are all complex quantities, so we can write them in polar form [tex]\begin{align*} V & = V e^{j\phi_V} \\ I & = I e^{j\phi_I} \\ Z & = Z e^{j\phi_Z} \end{align*}[/tex] where V and I correspond to the amplitude of the oscillations. Now Ohm's Law says [tex]V = IZ = (I e^{j\phi_I})(Z e^{j\phi_Z}) = IZe^{j(\phi_I + \phi_Z)}[/tex] from which you can see that [itex]V = I Z[/itex] and [itex]\phi_V = \phi_I + \phi_Z[/itex]. So you have two common approaches to the problem. You can work with V, I, and Z as complex numbers, use complex algebra, and grind everything out. This method is straightforward, but it's prone to errors because you're dealing with j's all over the place. The other approach is to work with V, I, and Z, which are real numbers, and figure out the phase relationship using the phasor diagram. It may seem a bit more complicated at first, but once you understand it, it's easier to remember and work with. 


#8
Mar2211, 09:11 AM

P: 23

I tried the second method you mentioned using my results from the link above. I think what I've done is correct. I'm not sure if I'm missing any more information Although it isn't to scale or in a presentable format, I think it's all there. http://img692.imageshack.us/img692/4722/21313865.jpg 


#9
Mar2211, 11:58 AM

Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 11,868

The image isn't loading here.



#10
Mar2211, 06:38 PM

P: 23

Try the attachment 


#11
Mar2311, 12:24 AM

Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 11,868

Looks good!



#12
Mar2311, 03:29 AM

P: 23

Thank you very much for your help. My lab report is now complete and ready for submission :D
Also, a side question, in the lab report, he asked us to provide two phasor diagrams. One for 1000Hz and another for 3000Hz. They both appear to be roughly 1KHz above and below the resonance frequency which I calculated to be 1930.04 Hz. Apart from the relationship of the phase between the elements, I'm not sure what I'm supposed to learn from the two phasor diagrams. Heres the second phasor diagram I did. As before, it's not to scale or in a presentable format. http://img813.imageshack.us/img813/7845/82891587.jpg 


Register to reply 
Related Discussions  
Drawing phasor diagram  Engineering, Comp Sci, & Technology Homework  0  
Power Factor and Phasor Diagram  Engineering, Comp Sci, & Technology Homework  2  
Phasor diagram/problem...[ASAP]  Introductory Physics Homework  0  
Phasor Diagram  Introductory Physics Homework  1  
Phasor Diagram  Introductory Physics Homework  0 