Ultimate Guide to Solving Combinatorics Problems | Learn with :zzz: Tricks

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Homework Help Overview

The discussion revolves around combinatorics problems, specifically focusing on arrangements and subsets involving integers and geometric configurations. Participants are exploring various approaches to solve these problems while clarifying the original questions posed.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss reducing complex problems to simpler forms and identifying patterns. There are inquiries about the exact wording of the questions and the interpretation of subsets. Some participants suggest specific arrangements and calculations related to subsets and intersections.

Discussion Status

The discussion is ongoing, with participants offering guidance and asking for clarifications. There are multiple interpretations of the problems being explored, and some participants express confusion while seeking further explanations.

Contextual Notes

Some participants mention constraints such as the requirement that no two identical elements can be adjacent and the condition that no three points can be collinear. There is also a reference to the difficulty of challenge problems compared to regular test questions.

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2. Reduce the problem to a simpler one and find a pattern. For example, in a 2x2 square only 4 triangles have this property.
3. Could you give the exact wording of the question or rephrase it? I am unsure if you mean one quarter of all subsets of integers 1,2,3...m with three elements or not.
 
1> How many arrangements are there such that no two A's are beside each other?
2> shouldn't be a problem ... straightforward (only thing to remember ... 3 points cannot be collinear)
3> how many 3-subsets can you form? (call this A)
How many 3-subsets can contain integer 5? (call this B)
1/4 * A = B ... solve for m
4> no three segments cross at any point ...
therefore atmost two segments can cross each other ...
and every crossing of two segments produces 1 intersection point ...
so ??

-- AI
 
Could you give the exact wording of the question or rephrase it? I am unsure if you mean one quarter of all subsets of integers 1,2,3...m with three elements or not.

a subset with 3 elements

TR.. I am so lost

could u explain it a lil more?

and number one i know its ez but I can't seem to get it
 
1> How many arrangements are there such that no two A's are beside each other?

a .. First arrange the B's and y's? in how many ways can u do this?
b .. amongst 6 B's and 7 y's there are 14 places where i can place A (why do i do this ? u see this way no two A will be beside each other)
c .. in how many ways can i arrange the A's in these 14 places

Can u proceed from here ... ??

shouldn't be a problem ... straightforward (only thing to remember ... 3 points cannot be collinear)

Look at what i gave in the brackets ... can u see how to pick the points then?

how many 3-subsets can you form? (call this A)
How many 3-subsets can contain integer 5? (call this B)
1/4 * A = B ... solve for m

Can u find A and B? (atleast A is pretty simple)

4> no three segments cross at any point ...
therefore atmost two segments can cross each other ...
and every crossing of two segments produces 1 intersection point ...
so ??

How many segments are given?
In how many ways can i choose 2 segments out of the given number of segments?

-- AI
 
TR.. ur help is greatly appreciated

A .. First arrange the B's and y's? in how many ways can u do this?
you can arrange this in 13! ways because that's how many total letters there are?

i LOST you from here :(

Look at what i gave in the brackets ... can u see how to pick the points then?


This i don't get at all


Can u find A and B? (atleast A is pretty simple)
got this thanks

and the last one i don't get at all too

man... i raped the test on this unit, but the teahers chellenge sets are HARD
 
Anyone?
 
can the mods delte this thread pleez
 

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