Help with Problem 25 and Other Math Problems

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Homework Help Overview

The discussion revolves around a set of math problems, specifically focusing on problem number 25, which involves a square with a given diagonal. Participants are also reviewing previous problems and their answers.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the sides of a square and the diagonal, with some attempting to apply Pythagoras' theorem. Questions arise about the exact nature of the problem and the calculations involved in finding the side lengths.

Discussion Status

The discussion is active, with various participants offering insights and questioning assumptions. Some guidance has been provided regarding the application of Pythagoras' theorem, but there is no explicit consensus on the correctness of the previous answers or the approach to problem 25.

Contextual Notes

Participants are reviewing their answers to earlier problems and questioning the accuracy of those answers, indicating a need for clarification on the problem setup and assumptions.

EggNest
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Hello everyone,

I need help with a couple of problems, right now I'm focusing on number 25.

http://img24.exs.cx/img24/2291/probs.gif

Also, if any of you have time, could you please tell me if I have missed any so far. Thanks.

22. A= 3768.2 units^2
23. A= 25.3 units^2
24. A= 5.4 units^2

And now if I could just get some help with the others...
 
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Now, you've got a square with the diagonal given, right?
So, what's your problem, exactly?
 
arildno said:
Now, you've got a square with the diagonal given, right?
So, what's your problem, exactly?
I need help going about finding the length of the sides
 
Sure enough, but:
1) You've got a square, right?
So, how does then the vertical side compare in length to the horizontal side?
2) Try to set up Pythagoras' theorem with the diagonal as the hypotenuse..
 
The length of all the sides would be 7.5 sqrt(2) right?
 
We have C from Pythagoras' therom
[tex]a^2 + b^2 = c^2[/tex]

however for a square
[tex]a=b[/tex]

so
[tex]a^2 + a^2 = c^2[/tex]
[tex]2a^2=c^2[/tex]

[tex]2a^2=15^2[/tex]
[tex]2a^2=225[/tex]


since area of a square is just a*b and a=b
area equals a*a or a^2 so divide the two out
[tex]a^2=\frac{225}{2}[/tex]
 
I believe 22 is wrong
23 is right rounded
24 is right rounded
 
Last edited:
22. by law of sines

[tex]\frac {73}{\sin{\theta}}=\frac{x}{\sin{\theta}}[/tex]

therefore must also be 73
73*73*.5 = 2664.5
 

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