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find voltage between two nodes |
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| Mar24-11, 03:38 PM | #1 |
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find voltage between two nodes
1. The problem statement, all variables and given/known data
Find voltage between node 1 and node 2 2. Relevant equations What is the algorithm? 3. The attempt at a solution R1=4 Ohms R2=5 Ohms R3=8 Ohms R4=3 Ohms R5=6 Ohms R6=7 Ohms Eэ=20 V E3=17 V E5=15 V |
| Mar24-11, 03:47 PM | #2 |
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use balanced wheat stone bridge thing
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| Mar24-11, 03:55 PM | #3 |
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Do I need second Kirhgoff rules' equations for every loop?
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| Mar24-11, 04:01 PM | #4 |
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find voltage between two nodes
try "balanced wheat stone bridge"
you wont need Kirhgoff rules here:http://en.wikipedia.org/wiki/Wheatstone_bridge |
| Mar24-11, 04:04 PM | #5 |
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hi builder_user!
![]() 'fraid so!
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| Mar24-11, 04:20 PM | #6 |
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What's the next step after Kirchgoff's rules?What do I need to find?I know current in every branch.
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| Mar24-11, 04:29 PM | #7 |
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You want the voltage between nodes 1 and 2. Use the current you found for the first loop (leftmost) using Kirchhoff to determine the voltage across R1. Then do the obvious voltage sum.
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| Mar24-11, 04:35 PM | #8 |
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i1=3.7A
U=Eэ-i1*R1=5.2V? And the final result -- 20(Eэ)+5.2(U)=25.2V? |
| Mar24-11, 04:49 PM | #9 |
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That's not the value I get for i1. Better check your derivation.
EDIT: My error. Redoing my sums I see that i1 is indeed about 3.7A. |
| Mar24-11, 05:14 PM | #10 |
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| Mar24-11, 05:17 PM | #11 |
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Wasn't it the voltage between nodes 1 and 2 that you were looking for?
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| Mar24-11, 05:23 PM | #12 |
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but i's only I1.
Or R1*I1 - is the result? |
| Mar24-11, 05:24 PM | #13 |
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Very sorry. I see that your figure of 3.7A for i1 and about 5.2V for the voltage between nodes 1 and 2 look okay.
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| Mar24-11, 05:36 PM | #14 |
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| Mar24-11, 05:46 PM | #15 |
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Again, sorry about that.
15 pages of A4? That seems like a lot for just three loops. What method are you using to solve the equations? |
| Mar24-11, 05:50 PM | #16 |
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I got this result(3.7) by different methods.So if it's wrong - all my work is wrong |
| Mar24-11, 06:04 PM | #17 |
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I see, so this is just one exercise for the given schematic.
It seems to me that a KVL loop approach is the most straight forward for this particular question, since you really only need to solve for the current in the first loop. Have you learned the method to directly write (by inspection) the matrix form of the equations? That allows you solve for the currents using a matrix method (such as Cramer's Rule), which takes only a few lines. |
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