What power is needed to create such a constant force?

  • Context: Undergrad 
  • Thread starter Thread starter Piewie
  • Start date Start date
  • Tags Tags
    Constant Force Power
Click For Summary

Discussion Overview

The discussion revolves around the power required for a rocket to create a constant upward force equal to the gravitational force, allowing it to "float" above a launch platform. Participants explore the relationship between force, power, and the dynamics of rocket propulsion, considering various scenarios and assumptions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Pieter initiates the discussion by asking about the power needed to create an acceleration of 9.81 m/s² for a 1 kg object, noting that a constant force of 9.81 N is required.
  • One participant explains that the power required to maintain that force depends on the speed of the object, using the formula P = Fv.
  • Another participant suggests that maintaining a constant force requires increasing power over time, providing a formula involving force, acceleration, and time.
  • Pieter clarifies that the actual question pertains to the power a rocket must deliver to match the gravitational force without upward or downward speed, except for the exhaust products.
  • One participant argues that for a rocket to "float," the upward force must equal the gravitational force, questioning the relevance of power in this context.
  • A later reply states that a stationary rocket motor delivers zero power, as work is not being done when the velocity is zero, while noting that energy is still being transferred to the exhaust.
  • Another participant emphasizes that the question is meaningless in terms of power, as no work is being done to hold the rocket at a stationary position, despite energy being expended in burning fuel.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between power and the force required for a rocket to float. Some argue that power is irrelevant in a stationary context, while others attempt to relate it to the dynamics of exhaust and thrust. The discussion remains unresolved with multiple competing perspectives.

Contextual Notes

Participants highlight the complexities of defining power in the context of a stationary rocket, with discussions on the efficiency of fuels and the mechanics of thrust generation. There are unresolved assumptions regarding the definitions of work and energy transfer in this scenario.

Piewie
Messages
9
Reaction score
0
Maybe this problem is easy to solve, but I can't find a way out.

I need to know what power is needed to create an acceleration of 9.81 m/s^2.
For an object with a mass of 1 kg.

A constant force of 9.81 N is needed (that's easy :rolleyes: ).

But what power is needed to create such a constant force?
There is no friction.


Thanx 4 your help,
Pieter
 
Physics news on Phys.org
If a force of 9.81 N is applied to a 1 kg object, it will accelerate. The power required to maintain that force on the object will depend on the speed of the object: P = Fv. (Power is the rate at which work is done or energy is transferred.)
 
If you are keeping the force constant, you'll have to put in more and more power as time passes.

You can calculate it from:

[tex]P = \vec{F} \cdot \vec{v}[/tex]

at any time when the velocity is v.

So, basically at any time t,

[tex]P = F \times a \times t[/tex]


spacetime
www.geocities.com/physics/index.html
 
Thanx a lot, but unfortunately these answers only solve a part of my problem.

The actual question is: what power must a rocket deliver so that its upward force equals the gravitational force. So the rocket will 'float' above the launch platform.

There is no upward or downward speed, except for the exhaust products.

Pieter
 
In order for the rocket to "float" above a platform, the upward force must be exactly the same as the gravitational force: gm. I don't see what that has to do with "power" (work done per second). You could for example, "float" the rocket by putting it on a table which would exert the correct force while doing no work at all.
 
Piewie said:
Thanx a lot, but unfortunately these answers only solve a part of my problem.

The actual question is: what power must a rocket deliver so that its upward force equals the gravitational force. So the rocket will 'float' above the launch platform.

There is no upward or downward speed, except for the exhaust products.

Pieter
:smile: zero
Intentional or otherwise, this is a "trick question". A stationary rocket motor delivers zero power to the rocketship. As someone already said in this thread, w=f*v and when v=0, w=0.

Now, if you want to figure out how much power is being delivered to the exhaust, that will be nonzero. However, there's no single answer. If the thrust (force) needed is f then

[tex]f = v_{exhaust} \cdot \frac{dm}{dt}[/tex]

as you probably already know. But you can achieve the needed f value with many different combinations of v_e and dm/dt, and each different combination will yield a different rate of energy transfer into the exhaust.

If one packet of exhaust is dm, and exhaust velocity is v_e, then one packet of energy into the exhaust is

[tex]dE = \frac{1}{2} \cdot dm \cdot v_e^2[/tex]

Divide through by dt and you've got power.
 
Last edited:
Piewie said:
Thanx a lot, but unfortunately these answers only solve a part of my problem.

The actual question is: what power must a rocket deliver so that its upward force equals the gravitational force. So the rocket will 'float' above the launch platform.

There is no upward or downward speed, except for the exhaust products.

Pieter
The question is quite literally meaningless. Work is not being done on such a rocket so the time rate of change of the energy of the rocket is zero. Power is the rate at which work is being done and in this case there is no work being done. E.g. it takes zero energy to let a rocket stay at a given location such as sitting on the ground on the launch pad.

However, rocket fuel is being burned and energy is being changed from one form to another at a given rate. This energy goes into the chaging the kinetic energy of the gas particles and thus giving them momentum. This momentum serves to impress a force on the rocket. But there is no direct relationship between this rate and the weight of the rocket since some fuels will be more efficient than others. This is akin to saying "How much energy do I need to expend in order to hold up a bucket full of water?" The work done on such a bucket, while holding it at a particular height, is zero. But energy is being burnt by your body in order to accomplish this.

Pete
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 41 ·
2
Replies
41
Views
5K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 95 ·
4
Replies
95
Views
8K