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QCD gluon propagator in axial gauge, polarization sum |
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| Apr1-11, 12:17 PM | #1 |
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QCD gluon propagator in axial gauge, polarization sum
Hi!
I have a process with multiple feynman diagrams where gluon propagators occur. When I use an axial gauge for the gluon propagator, do I have to use the same n-vector for every propagator? Following this I wonder whether I can use the same n-vector for every polarization sum in axial gauge or have to take different ones. Thanks, Tobias gauge field propagator in general axial gauge: [tex] G_{\mu\nu}^{ab}(q,\alpha)=\frac{-i\delta^{ab}}{q^{2}}\left(-g^{\mu\nu}-\frac{q_{\mu}n_{\nu}+q_{\nu}n_{\mu}}{qn}+q_{\mu}q_{\nu}\frac{n^{2}+\alp ha q^{2}}{(qn)^{2}}\right) [/tex] |
| Apr1-11, 02:58 PM | #2 |
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It seems pretty clear that in deriving the propagator above, one assumes that the vector [tex]n_\mu[/tex] doesn't vary with position. If it did, you would have to compute it's Fourier transform and the momentum space Feynman rules would be more complicated. Similarly, [tex]n_\mu[/tex] is independent of gauge indices, so there's no freedom to choose different values within a given computation.
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| Apr1-11, 04:23 PM | #3 |
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You can use a different gauge for the internal gluons (different from the external legs), but each internal gluon must be in the same gauge. Changing the vector n is a form of gauge transformation. |
| Sep20-12, 04:42 AM | #4 |
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QCD gluon propagator in axial gauge, polarization sum
I'm fully aware that this post is over one year old, but could someone provide a source for the above statement or at least scetch if and why this is true?
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