Angular Momentum/Impulse Problem


by cdbowman42
Tags: angular momentum
cdbowman42
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#1
Apr21-11, 04:18 PM
P: 14
[b]1. A 1.8 kg, 20 cm diameter turntable rotates at 160 rpm on frictionless bearings. Two 500 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diagonal, and stick. What is the turntable's angular velocity, in rpm, just after this event?


[b]2. Angular momentum(L)=angular velocity(w)*moment of inertia(I)


[b]3. I'm confused as to whether or not to appraoch this as a conservation of momentum problem or some other way. I think I would need to know the velocities of the blocks before they hit to to this.
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olivermsun
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#2
Apr21-11, 04:21 PM
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Do the blocks carry with them any angular momentum of their own? (It seems the problem is set up to hint that they do not).
cdbowman42
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#3
Apr21-11, 04:22 PM
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Thanks! thats all I needed!

tiny-tim
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Apr21-11, 04:23 PM
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Angular Momentum/Impulse Problem


hi cdbowman42!
Quote Quote by cdbowman42 View Post
I think I would need to know the velocities of the blocks before they hit to to this.
hint: what was their angular momentum about the axis, before they hit?

(assuming they fell vertically at speed v)
AlexChandler
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#5
Apr21-11, 05:04 PM
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I would think about it in the following way

[tex] \int \tau dt = \Delta ( I \omega) [/tex]

where [tex] \int \tau dt [/tex] is the angular impulse and [tex] \Delta (I \omega) [/tex] is the change in angular momentum.

We can see that no vertical torque is exerted on the turntable, so the angular momentum must remain constant.

Then we must have

[tex] (I \omega)_{initial} = (I \omega)_{final} [/tex]


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