Calculating Arc Length in Multivariate Calculus

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SUMMARY

The discussion focuses on calculating the arc length of the vector function r(t) = <3t, 4cos(t), 4sin(t)> from t=0 to t=1. Participants confirm that the derivative r'(t) equals 5, leading to an integral calculation that also results in 5 for the arc length. The geometric interpretation involves a right triangle with a base of 4 and a height of 3, suggesting a cylindrical wrapping around a radius of 4. The conclusion is that the calculated arc length of 5 is indeed correct.

PREREQUISITES
  • Understanding of vector functions in multivariate calculus
  • Knowledge of derivatives and integration techniques
  • Familiarity with the arc length formula in calculus
  • Basic geometric concepts related to right triangles and cylinders
NEXT STEPS
  • Study the arc length formula for parametric curves in multivariate calculus
  • Explore the geometric interpretation of vector functions
  • Learn about the applications of arc length in physics and engineering
  • Investigate the properties of cylindrical coordinates in calculus
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Students and educators in multivariate calculus, mathematicians interested in vector functions, and anyone seeking to understand the geometric implications of arc length calculations.

crazynut52
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here is the problem, and I can't seem to get very far,

compute the length of r(t) = <3t, 4cost, 4sint> from t=0 to t=1

i know the formula is integral from 0 to 1 of length of r'(t)

but I keep coming up with 5, and it doesn't seem right, can someone please confirm or deny this. Thanks
 
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that seems to be what i get too. r'(t) = 5, so when you integrate this from 0 to 1 it gives you 5 again.
 
If you look at what you've plotted, i believe it is the hypotenuse of a right triangle with base 4 and height 3 wrapped around a cylinder [of radius 4].
 

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