A positive definite Hermitian Form

[Try hard]

In this question I let "x1t , x2t, x3t " be the conjugate of x1, x2, x3

The hermitian form
Hc(x) = c*x1t*x1 + 2*x2t*x2 - i*x1t*x2 + i*x2t*x1 + x1t*x3 + x3t*x1
+i*x2t*x3 - i*x3t*x2 (sorry, it`s a bit messy)

For which value of c is Hc ositive definite?

I have tried to find the eignvalue in terms of c by trying to solve the
charactiristic polynomial, but seems too complicate to do, I`ve also tried
to solve by completing the square but not so successful.
So is there any way to solve this without using computer softwares like
maple? Thanks

 

[fresh_42]

The determinant $\operatorname{det}(H_c-\lambda I)=0$ yields (if I didn't make a mistake)
\begin{align*}
0&=(\lambda-u)(\lambda-v)(\lambda-w)\\&=\lambda^3-(u+v+w)\lambda^2+(uv+uw+vw)\lambda-uvw \\
&=\lambda^3-(2+c)\lambda^2+(2c-3)\lambda +c
\end{align*}
For positive definiteness we need $u,v,w > 0$, i.e. $uv+uw+vw =2c-3 >0$ and $uvw=-c>0$, thus $\frac{3}{2} < c < 0$ which is not possible.