
#1
May1211, 07:52 AM

P: 18

How do I find the d{flux}/dtime in the faradays law? The problem i'm facing i need to flux which depends on B and area. I have a coil of wire which is about 6 inches away from the center which hold a permanent magnet. How do I find the B [flux density] in the coil wire and how do find the flux change with respect to time? I know the how fast the magnet is moving straight up but i have NO idea how to find the Bflux lines passing through the wire.




#2
May1211, 01:23 PM

P: 58

I think you'll find this interesting:
http://en.wikipedia.org/wiki/Faraday's_law_of_induction If you're trying to find a numerical solution to a particular problem then the wiki article will show the right equations; if you're asking someone here to {do your homework for you} give help on how to apply the equations then you need to give all the info in the problem set for you. 



#3
May1211, 01:28 PM

P: 18

its more of a project, i read hte faradays wiki page, the page doesn't mention anything about measuring change in flux density as you go away from a permanent magnet. I need to find the best line of fit by plotting the change in flux with distant and derive it with respect to time to find d{flux}/dt = induced voltage




#4
May1211, 01:32 PM

P: 18

finding the change in flux
all it has is B(r,t)... what i have is magnet with all the properties known radial distance to the coil of wire, about 9 cm. I need to find the amount of flux on it. I also need to find the flux on the wire when the manget moves vertically up with 1cm increments.
I have no clue how to do it. Do I need a simulation software?it? Is there similar equation to force of gravity one? Like the further away you are, the lesser force of between two masses which is inversely proportional to square distant? I know flux density isnt constant everywhere! 



#5
May1211, 01:35 PM

P: 58

Yes, the equation is of exactly the same form as the gravity equation.




#6
May1211, 03:12 PM

P: 18

how can tell me flux density over a specific area from r distance from the source of magnetic flux?




#7
May1211, 04:18 PM

P: 315

I don't know if I understand your question correctly, but it seems like you need the [tex]\vec{B}(\vec{r},t)[/tex] for your permanent magnet so you can calculate the flux density that goes through your coil of wire.
I've never seen an equation for the [tex]\vec{B}(\vec{r})[/tex] of a permanent magnet in physics problems. All I've seen is equations for the [tex]\vec{B}(\vec{r})[/tex] of electromagnets, which can be found using the BiotSavart law. But I GUESS you can find one for a permanent magnet if you assume it to be a lattice, find the magnetic dipole moment [tex]\vec{\mu}[/tex] of the typical lattice point (atom or molecule), find the [tex]\vec{B}(\vec{r})[/tex] for a generic [tex]\vec{r}[/tex] (this would be the magnetic field due to a single atom/molecule), and spatially integrate over the structure of the lattice to account for all the lattice points. Maybe these links will help if you want to do that. http://en.wikipedia.org/wiki/Magneti...ent_of_an_atom http://en.wikipedia.org/wiki/Permane...tomic_currents http://en.wikipedia.org/wiki/Magneti...manent_magnets http://en.wikipedia.org/wiki/Dipole#...agnetic_dipole http://en.wikipedia.org/wiki/Magneti...oulomb.27s_law But since you said it's a project, maybe you have the physical material handy. I'd take an experimental approach in that case, and measure the induced voltage of the coil of wire and the position of the magnet at the same time. Then from Faraday's law of induction, the induced voltage is proportional to [tex]\frac{d \phi}{d t}[/tex] where [tex]\phi[/tex] is the flux. 



#8
May1311, 06:28 AM

P: 18

Thanks for link. I never knew the magnets were anything like 'dipole'. After going throught the pages, I think found the equation I was looking for.
Just to clear myself to you what I'm trying to do. I have a coil of wire in a rod shape around a magnet, not a simple coil around a magnet. The circular rod is filled with N number of wires. The diameter of the coil is known and the distance between the coil and center magnet also known. I just want to find the amount of flux entering the surface area of the wire. Anyway, returning to the equation, I don't get it. :'( The type of magnet is known, but how do I find its dipole movement? What the difference between 'lamba' and 'r'? Aren't the the same thing distance from the center axis of the magnet? If 'p' is the distance from the zaxis... wut is 'r' then?????? 



#9
May1411, 02:09 AM

P: 315

I had computer trouble, hence the late reply.
It looks like the [tex]r[/tex] comes from the spherical coordinate system, and [tex]\rho[/tex] comes from the cylindrical coordinate system. [tex]\lambda = 90^{\circ}  \theta[/tex] is an angle which can be calculated using the spherical coordinate [tex]\theta[/tex] [tex]\rho[/tex] is the distance from the [tex]z[/tex] axis, and [tex]r[/tex] is the distance from the origin. From the Pythagoras's law, [tex]r^{2} = \rho^{2} + z^{2}[/tex]. I don't know if a whole magnet could be accurately approximated by a single dipole moment. But it might be possible. What I meant in the last post was to take in to account all the molecules in the magnet, and assign each of them a magnetic dipole moment, and then calculate the total magnetic field from all of those molecules. But reading about this further, it seems more complicated than I thought. I don't know how to find the individual magnetic dipole moments of molecules (my quantum mechanics is not that good at the moment). The temperature has to be taken in to account too. The Atomic, Solid State, Comp. Physics forum might be a good place to ask how to model a permanent magnet. Solid state physicists do that stuff for a living. Like I said before, you could also take an experimental approach. If you can measure the voltage between the two ends of the coil at any given time [tex]t[/tex], then that is equal to the electromotive force [tex]\varepsilon[/tex] in the Faraday's Law, [tex]\lvert \varepsilon \rvert = N \lvert \frac{ d \phi_{B} }{ d t } \rvert [/tex], where [tex]N[/tex] is the number of coils. So you can measure the rate of change of flux. You can integrate this(you could do it numerically) to find the flux [tex]\phi_{B}[/tex]. But there will always be an unknown constant. One suggestion I have to overcome this is start with the magnet very far away from the coil so the initial flux is zero ([tex]\phi_{B 0} = 0[/tex]) so that constant is zero, and measure [tex]\varepsilon[/tex] with [tex]t[/tex]. If you also record the position of the magnet with time, then you can find out how the position of the magnet is related to the total flux through the coil. By the way, I found this cool video of a fluxgate magnetometer. May I ask why you need to find the flux through the coil? 



#10
May1411, 07:18 PM

P: 18

its just for a simple project. i really don't want to make a practical of it.. 



#11
May1411, 07:55 PM

P: 315

It looks to me as if finding the [tex]\vec{B}(\vec{r})[/tex] for a permanent magnet theoretically would be extremely difficult because it depends on the atomic properties of the magnet. That means quantum mechanics, oscillation of the atoms due to temperature, interactions of atoms with each other, all come in to play. Ising model was an attempt do this, but it is EXTREMELY more simplified than real life. To my knowledge, there is still no analytical solution for the 3D case. You can write whole scientific papers about it and still have no solution.
Finding the [tex]\vec{B}(\vec{r})[/tex] for simple electromagnets (coils, solenoids etc.) theoretically are comparatively simple because it only depends on the magnitude and spatial distribution of the current going through the electromagnet. So I think unless you can replace your permanent magnet with an electromagnet, you have to do a practical experiment to find out the flux through the coil. 



#12
May1511, 12:27 AM

P: 18

How about we assume the permanent magnet has the same properties of an electromagnet. The permanent magnet which I chose was Neyodium Iron Boron magnet with its magnetic properties known. If we assume the permanent magnet behaves like a electromagnet, how will I then calculate the flux density on a specific area constant area as the magnet moves up and down?
My main goal is to find the amount of current induced in the coil of wire with a velocity equation name. The whole thing is simple faraday's law induction experiment but instead of the coil surround the magnet, the coil is more wrapped in a circular rod fashion as shown in the figure with it moving vertically straight up at, lets say 10m/s. 



#13
May1511, 12:43 AM

P: 315

The [tex]\vec{B}[/tex] for an electromagnet depends on the current. For example, look at the equation for a solenoid. It changes with the current [tex]i[/tex]. There is no analogous parameter for a permanent magnet.
What magnetic properties about your magnet do you know? 



#14
May1511, 12:54 AM

P: 18

I think i found what I was looking for take a look at it. http://www.magneticsolutions.com.au/...ormula.html#sr
it doesn't involve any dipole things you mentioned. >>I THINK THAT WAS IT<< but I'm trying to understand how the equation work. Like I want the field on the coil of wire with a plane perpendicular to the plane of screen [into the screen]. To give you a better model of my setup, it involves two magnet,side by side, surrounded by steel, then the coil of wires. below is the front cross section of the diagram. AFter going through the page, this is the equation which I see is the best for my setup, I will assume everything is in a block of steel with no air gaps or anything Couple of questions popped up
Because the equation doesn't have anything related to vertical distance, I can maybe use simple trig to cacluate the x component of distance as the magnet moves up [x1 and x2]. Though not accurate, it will be able to provide me with some results Or did I understand the whole equation wrong? :'( 



#15
May1511, 01:29 AM

P: 315

Nice! Thanks for the link. Maybe I can use it sometime.
Use of their equation require a [tex]B_{r}[/tex]. Do you know this value for your magnet? I mentioned magnetic dipole moments because I was thinking about calculating the magnetic field using the atomic structure of a magnet. The first three paragraphs on this page from their site gives a brief overview about the structure of a magnet. It would be great to know how they found out those equations. They haven't posted about it. 



#16
May1511, 01:40 AM

P: 18

please read my previous message.. I updated it..took a long time to edit it :p
? the type of magnet i'm using is Neodymium Iron Boron. ANd according to this random paper i found using google, its Neodymium Iron Boron (Br = 11.2T). http://www.google.com/url?sa=t&sourc...dEJA_w&cad=rja 



#17
May1511, 01:58 AM

P: 18

Btw, is it possible using FEM software? I have ansys but I don't know how to use it yet. I do have CAD model of whole setup. Maybe if you know, I can forward you the model to carry out the FEM. I don't have time right now to learn whole Ansys.
If I'm able to do what this author as done http://img687.imageshack.us/img687/8...lievahinov.pdf it will save me loads of time understand the equations and caclculating the time. But I find it more interested to actually solve all the equation and assume necessary conditions. 



#18
May1511, 03:04 AM

P: 315

Tell me if my interpretation of your diagram is incorrect. The two blue rectangles are the magnets. The three white rectangles (with one between the two blue rectangles and two outside them) are steel. I guess the purple squares are air? And the brown circles are your wires.
And if I also understand correctly you intend to change the setup of your magnet to the one they have given the equation for. The equation they have given is valid for a point along the central axis of the magnets. But I GUESS you can approximate that for the whole rectangular area between the magnets IF you have the magnets VERY CLOSE TOGETHER. Then if you can move the magnet(or move the coil), so the coil passes between the rectangular space between the two magnets, and keep the plane of the coil perpendicular to the central axis of the magnets, the flux through the coil [tex]\phi_{B}[/tex] is [tex]\phi_{B} = B \cdot A[/tex], where [tex]B[/tex] is the flux density and [tex]A[/tex] is the area of the coil that lies in the rectangular space, right? So [tex]\frac{ d \phi }{d t} = B \frac{d A }{d t}[/tex]. If the magnet is rectangular and the length of the magnet is INSIDE THE RECTANGULAR SPACE is [tex]l[/tex] (the coil is moving relative to the magnet in the direction of [tex]l[/tex]), and the width of the magnet is [tex]w[/tex], then [tex]\frac{ d A}{d t } = w \frac{ d l }{ d t }[/tex]. So [tex]\frac{ d A}{d t }[/tex] will be positive as the coil enters the space between the two magnets and negative as it exits the space between the two magnets (The direction of the voltage will change). The exact equation will depend on how the magnet or the coil moves (will it be falling under gravity or moving at a constant velocity or etc...). They're very clear that the equation is for the distance along the central axis of the magnet. So going off axis will not work. But if you keep the magnets very close together, there will be an almost constant flux density between them, but there will be almost none outside. So the coil will suddenly enter an area of nonzero constant flux density. I have no expertise with Finite Element Method or Ansys. 


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