rich_mmiv said:
Hi,
When air is heated to a point where it turns into a plasma, is there any equation which governs how much the gas expands in the explosion?
Thanks
You can treat a plasma pretty much as an ideal gas
As the nucear weapon FAQ suggests
NukeFaq
Perfect monatomic gases are of special interest to us here, not only because they are particularly simple to analyze, but because under many extreme physical regimes all matter tends to behave like a perfect monatomic gas (kinetic energy dominates other forms of energy present).
The law for adiabatic expansion and compression is given in the FAQ. Assuming the expansion is adiabiatic ignores the energy loss due to radiation. Presumably the expansion is happening quickly enough that the energy loss to radiation is small, even though the amount of radiation may be large. This assumption really needs to be checked. Assuming it's correct, we can write:
[tex]P * V^\gamma[/tex] = constant
where P is the pressure, V is the volume, and [tex]\gamma[/tex] is 5/3 for a monatomic gas
Combine this with the ideal gas law, and one should be able to find the solution to your question.
The ideal gas law is
P * V = N * R * T
P and V have been previously defined, N is the number of moles in the gas, R is the universal gas constant, and T is the temperature
There's a lot more info in the FAQ, it's worth giving a closer read if you are interested in this problem.
To discuss your particular problem in more detail, I am assuming we are heating up a some number of moles N of air originally at some temperature T to a new, much higher temperature T', dissasociating it in the process.
Assuming the air dissasociates, we will have some greater number of moles of the new gas N'. Since nitrogen is the main component of air, N
2 changing to N
1 will roughly double the number of moles of gas. This process will of course require a lot of energy. The small percentage of air that is triatomic, such as CO2 and water vapor will make this factor slightly larger than 2.
Originally we had P * V = N * R * T
Keeping the volume constant, the ratio of the new pressure to the old pressure (which would typically be atmospheric pressure) is
P'/P = (N'/N) * (T'/T)
where N'/N should be roughly 2 as I argued previously.
If the expansion then continues adiabatically until P'=P, the volume should increase by a factor of
[tex](\,\frac{N'}{N}\frac{T'}{T}\,)^{\frac{1}{\gamma}}[/tex]
Disclaimer - I think this analysis is correct, but I don't offer a guarantee, thermo isn't one of my strong points.