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Graph of inverse square law for radiation intensity 
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#1
Jun1411, 05:26 PM

P: 13

If I=s/4pir^{2} would It be correct to write this in terms of logs like this:. lnI=(lns/4pi)2.lnr Also how could this relate to y=mx+c? I think it's y=lnI. X=lnr. m= 2 and c= lns/4pi. Is this correct? Thank you



#2
Jun1411, 09:36 PM

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PF Gold
P: 5,197

ln(ab^{c}) = ln(a) + ln(b^{c}) (the log of a product equals the sum of the logs of the individual factors in the product). and ln(b^{c}) = cln(b) EDIT: It should be m = 2, NOT m = 2. 


#3
Jun1411, 09:42 PM

HW Helper
Thanks
P: 10,381

You wrote m=2 which results m=2, a positive slope of the ln(I)lnr graph. Is it right?
ehild 


#4
Jun1511, 02:27 AM

P: 13

Graph of inverse square law for radiation intensity
Ah of course it's not m, seems like I confused myself. Thank you



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