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Parallel voltage sources circuit |
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| Jul9-11, 02:15 AM | #52 |
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Parallel voltage sources circuit*comes back* Oh right there's an exercise to solve. But if I didn't have....if I didn't....I'd so storm off right now! ![]() As if! |
| Jul9-11, 02:18 AM | #53 |
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Hmm.... would it be reasonable to ask an easier parallel voltage sources problem before I try this one? I really want more practice on basic circuits with parallel voltages first...unless you think it would be redundant to me now? Whatever you tell me
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| Jul9-11, 02:28 AM | #54 |
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I've really decided it's too complex since we're not gonna have something THAT difficult on the test!
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| Jul9-11, 02:33 AM | #55 |
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I just love it when you're mad cyber grrr!!!
![]() *Sees you storming off* Wait! Come back! ![]() And do you recall Sauron who mispointed on a small one? It cost him everything!!! And yes, the difference is just a minus or a plus. Since you usually get dramatically different results if you make a mistake with one, it's an important part of the answer. |
| Jul9-11, 02:42 AM | #56 |
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Here's one that's more like what you ask for.
![]() Determine the currents I_1, I_2, and I_3 in the figure. Assume the internal resistance of each battery is 1.0 Ohm. I1, I2, I3 = __________ A What is the terminal voltage of the 6.0-V battery? Vt = _____ V |
| Jul9-11, 02:49 AM | #57 |
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That's a great one, thanks!
I'll work on it now!Sauron mispointed on a small one? I don't recalll that! Was that the book or the movie? |
| Jul9-11, 02:55 AM | #58 |
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Sauron misplaced one small ring, that was picked up by one small guy.
He never thought it would matter, especially since not even the great white wizard (Saruman) could withstand his corrupting power. :) (Both in the books and in the movies.) |
| Jul9-11, 03:08 AM | #59 |
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| Jul9-11, 03:10 AM | #60 |
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| Jul9-11, 03:28 AM | #61 |
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What are you unsure of? Or rather, what do you need to be sure? |
| Jul9-11, 03:33 AM | #62 |
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I'll take it as "you're right"
![]() No, I'm not "unsure" anymore, I looked at it for a while and it makes sense now!
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| Jul9-11, 03:35 AM | #63 |
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Darn! I'll have to cloak my responses more carefully!
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| Jul9-11, 03:47 AM | #64 |
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| Jul9-11, 05:25 AM | #65 |
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You have a mistake in your second equation.
And I would suggest doing the math, because I think you have not practiced it enough. Moreover, you have made the math harder for yourself because you took the entire enclosing loop instead of just the lower loop. |
| Jul9-11, 06:03 AM | #66 |
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I agree there is a mistake in the 2nd equation, but it may not be entirely mathematical.
It could be a conceptual one concerning voltage sources. Taking the larger loop only adds one additional term versus the bottom loop. Not a large enough difference in math to be concerned. Either way results in 3 equations with 3 unknowns, which may be solved using standard technique. |
| Jul9-11, 06:09 AM | #67 |
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The mistake is because I copied/pasted the first equation to the second equation to make the process of typing down the second equations easier, then I started deleting terms but I accidentally didn't delete the +12. It's just a typo type of mistake again, really
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| Jul10-11, 03:54 AM | #68 |
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