yjk91 said:Homework Statement
Two resistors, R1 and R2, are connected in series across a potential difference, ΔV0. Express the potential drop across each resistor individually, in terms of these quantities.
The Attempt at a Solution
R1 + R2 = Req
I = V0 / Req
drop at
V1 = V0 / (req) * R1
V2 = V0 / (req) * R2
i think this right?
Potential drop refers to the decrease in electrical potential energy that occurs as an electric current passes through a resistor. It is also known as voltage drop.
Potential drop is measured in units of volts (V) using a voltmeter. It is typically represented by the symbol ΔV or VR.
The potential drop across a resistor is affected by the resistance of the resistor, as well as the current flowing through it. It is also affected by the material the resistor is made of and the temperature of the resistor.
Kirchhoff's voltage law states that the sum of all voltage drops in a closed circuit is equal to the sum of all voltage sources. This means that the potential drop across each resistor in a series circuit will add up to the total voltage of the circuit.
In a series circuit, the potential drop across each resistor is proportional to its resistance. This means that the potential drop across a resistor can be calculated using Ohm's law: V = IR, where V is the potential drop, I is the current, and R is the resistance of the resistor.