Asteroid's orbital radius and speed

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Homework Help Overview

The discussion revolves around calculating the orbital radius and speed of an asteroid in the asteroid belt, given its orbital period of 5 Earth years. The context involves gravitational physics and orbital mechanics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need for the mass of the sun in the calculations and explore the use of Kepler's third law. There are attempts to derive the orbital radius using the provided formula, with some questioning the correctness of their period conversion from years to seconds.

Discussion Status

Some participants have offered guidance on the formula to use and have confirmed the general approach as correct. However, there is a lack of consensus on the period calculation, with participants seeking clarification on the conversion from years to seconds.

Contextual Notes

There is an ongoing discussion about whether the mass of the sun can be treated as a variable in the calculations. Additionally, the conversion of the orbital period from years to seconds is under scrutiny, indicating potential confusion about unit conversions.

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somebody help me start this question

The asteroid belt circles the sun between the orbits of Mars and Jupiter. One asteroid has a period of 5 Earth years. What is the asteroid's orbital radius and speed?

Thanks!
 
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I believe you need the mass of the sun, unless you are allowed to give your answer as a function of that variable. Use this formula:
[tex]T=\frac{2\pi r^{\frac{3}{2}}}{\sqrt{Gm_{sun}}}[/tex]
where G is the universal gravitational constant and T is the orbital period.
 
is this right

Sirus said:
I believe you need the mass of the sun, unless you are allowed to give your answer as a function of that variable. Use this formula:
[tex]T=\frac{2\pi r^{\frac{3}{2}}}{\sqrt{Gm_{sun}}}[/tex]
where G is the universal gravitational constant and T is the orbital period.
will the period be 31536000s. if it is, is this right:
r=[T*(sqrt(GM_sun)/2pi)]^(2/3)
[ 31536000*sqrt(6.67*10^(-11)*(1.99*10^(30)))/(2*pi)]^(2/3)
 
Check your period calculation again. Your method looks correct.
 
Sirus said:
Check your period calculation again. Your method looks correct.
opps
31536000*5?
 

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