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Help How can I find acute Angle theta? 
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#1
Aug1211, 02:41 AM

P: 25

How to find acute angle theta ,when tan 63 Degree = cot theta??Could anyone help me to find answer of this query.I need steps too as I am sooooo poor in mactematicuos .Final Answer of theta should be in degrees
Thanks in advance 


#2
Aug1211, 03:01 AM

P: 25

1. The problem statement, all variables and given/known data
Help !! How can I find acute Angle theta?? How to find acute angle theta ,when tan 63 Degree = cot theta??Could anyone help me to find answer of this query.I need steps too as I am sooooo poor in mactematicuos .Final Answer of theta should be in degrees Thanks in advance 2. Relevant equations I don't know,If I know these things,then I would have been the head of 'NASA' :) 3. The attempt at a solution 


#3
Aug1211, 03:13 AM

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P: 5,328

First step, instead of cot write it as tan, you are probably more comfortable with tan.
If you don't know what cot is, ask google. 


#4
Aug1211, 03:16 AM

HW Helper
P: 2,318

Help How can I find acute Angle theta?
cot is short for cotangent  which is short for complementarytangent. In the same way sin and cos are short for sine and complementarysine In the case of sine and cosine, the sine of an angle, and the complementarysine of the complementary angle are equal in value. eg, 41 degrees and 49 degrees are complementary [they add up to 90] compare sin 41 to cos 49  or if you prefer sin 49 to cos 41. The relationship between tan and cot is the same. 


#5
Aug1211, 03:49 AM

P: 25

Hi,thank you friends for the help,but it is not adequate to solve my problem.
I know simple mathematics like sin/cos=tan and cos/sin=cot, but not able to find a solution for my critical problem. I will repeat the query once again...Hope you can help me.... Determine the acute angle θ when tan 63° = cot θ. 


#6
Aug1211, 04:17 AM

P: 25

Nobody here to help me out...



#7
Aug1211, 04:20 AM

P: 70

It's simple.
Use the given equation to obtain tan(63)=cot[itex]\theta[/itex] arccot(tan(63))=[itex]\theta[/itex] Solving, [itex]\theta[/itex]=27 


#8
Aug1211, 04:23 AM

P: 25




#9
Aug1211, 04:30 AM

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#10
Aug1211, 04:33 AM

P: 25




#11
Aug1211, 04:39 AM

P: 25




#12
Aug1211, 04:48 AM

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P: 2,318

Write down an angle  eg 17 Using your calculator: Take tan 17 use 1/x, the reciprocal, on the answers now do inverse tan and write down that answer. repeat starting with an angle different to 17 degrees. Note anything? 


#13
Aug1211, 04:51 AM

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P: 2,318

If your calculator doesn't have a cot function, use the tan function followed by the 1/x function. [you best take the tan 63 to start with and write that answer down for reference. 


#14
Aug1211, 05:05 AM

P: 25

http://answers.yahoo.com/question/in...1201353AAYQeXG Determine the acute angle θ when tan 63° = cot θ. Tan63° =Cot θ Ie, 1.96261= Cot θ Arccot(1.96261)=Cot θ Ie, Cot θ=1.96261 Tan θ=1/1.96262 So, θ=Tan1(1/1.96262) Ans=27° 


#15
Aug1211, 05:36 AM

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P: 2,318

Tan θ = Cot (90  θ) or Cot θ = tan (90  θ) Similarly Sin θ = Cos (90  θ) or Cos θ = Sin (90  θ) so Tan 63 = Cot (90  63) = Cot 27 That is the complementary angle stuff I was trying to lead you to. 


#16
Aug1211, 07:06 AM

P: 86

Notice that tan(θ)=cot(90θ) for any θ.



#17
Aug1211, 08:19 AM

Math
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PF Gold
P: 39,544

This was posted in both "Precalculus Homework" and "General Mathematics" so I am merging the two threads.



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