Calculating Elementary Charge Using Millikan's Experiment Results

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SUMMARY

This discussion focuses on calculating the elementary charge using results from Millikan's oil drop experiment. The equation used is q = mgr/V, where q represents charge, m is mass, g is gravitational acceleration, r is distance, and V is voltage. The calculated charges for the oil drops are 1.12×10-18 C, 8.0×10-19 C, 3.2×10-19 C, and 9.6×10-19 C. To determine the elementary charge, one must find the greatest common divisor of these calculated charges, confirming that the elementary charge is an indivisible unit.

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  • Understanding of basic physics concepts, specifically forces and electric charge.
  • Familiarity with the equation q = mgr/V for calculating charge.
  • Knowledge of the concept of greatest common divisor (GCD).
  • Basic understanding of Millikan's oil drop experiment and its significance in physics.
NEXT STEPS
  • Research how to calculate the greatest common divisor (GCD) of multiple values.
  • Explore the principles behind Millikan's oil drop experiment in greater detail.
  • Learn about the significance of the elementary charge in physics.
  • Study the relationship between mass, voltage, and electric charge in electrostatics.
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High school students studying physics, educators teaching basic physics concepts, and anyone interested in understanding the fundamentals of electric charge and its measurement through experimental methods.

decamij
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Using BASIC physics, and being given some results of Millikan's experiment, how would i calculate elementary charge. Basic physics means using the following equation:


q = mgr
V

Here are some results:

mass (kg) voltage (V) distance (m)
3.2X10^-15 140.0 0.005
2.4X10^-15 147.0 0.005
1.9X10^-15 290.9 0.005
4.2X10^-15 214.4 0.005

i used the above equation to find the charge on each oil drop. Then what do i do?
P.S. I'm only in grade 12, and i only the basics of this topic. Please don't use crazy 4th year advanced physics.

Thanx a lot
 
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If you calculate the charge on the drop for each experiment, you get:
##1.12\times 10^{-18} C##
##8.0\times 10^{-19} C##
##3.2\times 10^{-19} C##
##9.6\times 10^{-19} C##
Assuming that the elementary charge is an indivisible unit tells you that the charge on an oil drop must be an integer multiple of the elementary charge (so you can have, e.g., 3, 8, or 17 charges on an oil droplet, but you can't have a fraction of a charge). With this knowledge, finding the elementary charge is as straightforward as finding the greatest common divisor of the charges on individual oil drops.
 

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