Vector and Basis Transformations

In summary, my problem is that x and y are coordinate as well as variables, which is throwing me off. I think the question is just too easy, and I don't understand what the new components of my V vector are.
  • #1
CatSails
5
0
Hi, I'm working through Schutz's intro to GR on my own, and I'm trying to do problems as I go to make sure it sinks in. I've encountered a bump in chapter 5, though. I don't think this is a tough problem at all, I think it's just throwing me off because x and y are coordinates as well as variables, if you know what I mean.

Homework Statement


Hopefully my latex tags work!
Let [tex] f= x^2 +y^2 + 2xy [/tex]
[tex] V \rightarrow (x^2 +3y, y^2+3x) [/tex]
[tex] W \rightarrow (1,1) [/tex]

So, among other things, I have to express f as a function of r and theta, and find the components of V and W in the r, theta basis. I thought I knew what I was doing, but the new components of my V vector are pretty ugly, which always makes me suspicious.

Homework Equations



[tex] x^2 + y^2 = r^2 [/tex]
[tex] x = rcos\theta[/tex]
[tex] y=rsin\theta[/tex]
[tex] V^{\alpha '} = \Lambda^{\alpha '}_{\beta} V^{\alpha} [/tex]

The Attempt at a Solution



Well, I'm pretty sure f is just [tex] f(r, \theta) = r^2 + 2r^2\cos\theta [/tex],
I'd rather not write out the matrix equation, but using the equation above for the transformation of vector components, and writing out V in r and theta as [tex] V \rightarrow (r^2\cos^2\theta +3r\sin\theta, r^2\sin^2\theta +3r\cos\theta) [/tex], and I've calculated the transformation matrix between cartesian and polar to have components from left to right, top to bottom, of [tex] \cos\theta, \sin\theta, -\sin\theta /r, \cos\theta/r [/tex], I get pretty ugly vector components for the new coordinate system (complete with things that don't simplify much, like cos^3 + sin^3, etc).
Does it look like I'm doing it right? Completely wrong matrix?
Thanks.
 
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  • #2
CatSails said:
Hi, I'm working through Schutz's intro to GR on my own, and I'm trying to do problems as I go to make sure it sinks in. I've encountered a bump in chapter 5, though. I don't think this is a tough problem at all, I think it's just throwing me off because x and y are coordinates as well as variables, if you know what I mean.

Homework Statement


Hopefully my latex tags work!
Let [tex] f= x^2 +y^2 + 2xy [/tex]
[tex] V \rightarrow (x^2 +3y, y^2+3x) [/tex]
[tex] W \rightarrow (1,1) [/tex]

So, among other things, I have to express f as a function of r and theta, and find the components of V and W in the r, theta basis. I thought I knew what I was doing, but the new components of my V vector are pretty ugly, which always makes me suspicious.

Homework Equations



[tex] x^2 + y^2 = r^2 [/tex]
[tex] x = rcos\theta[/tex]
[tex] y=rsin\theta[/tex]
[tex] V^{\alpha '} = \Lambda^{\alpha '}_{\beta} V^{\alpha} [/tex]

The Attempt at a Solution



Well, I'm pretty sure f is just [tex] f(r, \theta) = r^2 + 2r^2\cos\theta [/tex],
You left out a factor of sin theta in the second term.
I'd rather not write out the matrix equation, but using the equation above for the transformation of vector components, and writing out V in r and theta as [tex] V \rightarrow (r^2\cos^2\theta +3r\sin\theta, r^2\sin^2\theta +3r\cos\theta) [/tex], and I've calculated the transformation matrix between cartesian and polar to have components from left to right, top to bottom, of [tex] \cos\theta, \sin\theta, -\sin\theta /r, \cos\theta/r [/tex], I get pretty ugly vector components for the new coordinate system (complete with things that don't simplify much, like cos^3 + sin^3, etc).
Does it look like I'm doing it right? Completely wrong matrix?
Thanks.
Looks okay to me so far. What are you getting?
 
Last edited:
  • #3
You are right, I did leave out sin theta. That was happily just a typo/transcription error, though.

I think I do know what [tex] \hat{r}, \hat{theta}[/tex] are. They're the unit basis vectors in the r, theta coordinate system, corresponding to the radial direction and the angular direction, they're orthogonal, etc.
But it's also part of my confusion. The question specifically asks for the components of the vector. I know when you transform the basis vectors, the transformation is
[tex] e_{\alpha'} = \Lambda^{\beta}_{\alpha'} e_{beta} [/tex]
Where the unprimed labels are cartesian, and the primed in this case is the polar. That gives

[tex] e_r = \cos\theta e_x + \sin\theta e_y [/tex]
[tex] e_{\theta} = -r\sin\theta e_x +r\cos\theta e_y [/tex]

So I guess I don't understand how to combine these. The question specifically asks for the "V and W components on the polar basis, as functions of r and theta."

I calculated the components (which are ugly, which lead me here), but I never transformed the basis vectors. I suppose it's possible that the correct answer is a combination of the components I calculated and the coefficients that come from transforming the basis vectors, but I don't think so. I'm just not clear on this process, I guess.
 
  • #4
I guess I should put in my ugly vector: The answer I had got for the components of V is

[tex] r( r(\cos^3\theta + \sin^3\theta) + 3\sin\theta\cos\theta, \frac{3(\cos^2\theta-\sin^2\theta)}{r} +\sin^2\theta\cos\theta - \cos^2\theta\sin\theta) [/tex]

Thanks for the help, also!
 
  • #5
Okay, to think out loud for a moment:

I do think that the components of the vector are just those that I displayed above. The component transformation should not depend on the basis transformation, I think. It's really just that the answer I got was so ugly that I thought I must be wrong.
 
  • #6
The [itex]3\sin\theta\cos\theta[/itex] in the r-component is off by a factor of 2, but otherwise looks good.
 
  • #7
You are right, that should have been 6, not 3.
Thanks for the help!
 

1. What are vector and basis transformations?

Vector and basis transformations are mathematical operations that change the coordinates of a vector or the basis of a vector space. They are often used to simplify calculations or to represent a problem in a different coordinate system.

2. What is the purpose of performing a vector or basis transformation?

The purpose of performing a vector or basis transformation is to simplify calculations or to better represent a problem in a different coordinate system. It can also help to visualize and analyze data in a different way.

3. How is a vector transformed?

A vector is transformed by multiplying it with a transformation matrix. The transformation matrix is a square matrix that represents the new basis vectors of the transformed vector.

4. What is the difference between a vector transformation and a basis transformation?

A vector transformation changes the coordinates of a vector while keeping the basis of the vector space the same. A basis transformation changes the basis of the vector space while keeping the coordinates of the vector the same.

5. What are some real-world applications of vector and basis transformations?

Vector and basis transformations have various applications in fields such as physics, engineering, computer graphics, and data analysis. They are used to represent and analyze data in different coordinate systems, simplify calculations, and solve complex problems.

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