# Calculate how long it will take for the ice to melt?

by klilly
Tags: melt
 P: 3 1. The problem statement, all variables and given/known data A chilly bin has walls 5.90 cm thick and the total area of the walls is 0.700 m2. The chilly bin is loaded with 2.00 kg of ice at 0.00 °C and stood on a rack so that its entire surface is in contact with the air. The temperature on the outside of the chilly bin is 28.0 °C. If the chilly bin is made of styrofoam (kstyrofoam = 0.0100 J s–1 m–1 °C–1), how many hours will it take to melt all of the ice? (Note: Lfwater = 3.35 × 105 J kg–1) 2. Relevant equations I was given (L (water) x m (water))/ kA(Change in T/Change in thickness) But it didnt work out right 3. The attempt at a solution Answer is: 56 hours I have no idea how to get to this :(
 P: 610 law of thermal conduction says $$\mathcal{P}=kA\;\frac{\Delta T}{\Delta x}$$ where P is the power transferred, k is thermal conductivity, A is the area of the surface through which energy will flow, $\frac{\Delta T}{\Delta x}$ is temperature gradient. $\Delta T$ is the temperature difference between inner and outer surface, $\Delta x$ is the thickness of the bin. now we have been given , for chilly bin (made out of styrofoam) k= 0.0100 J s-1 m-1 °C-1 A=0.700 m2 delta T=28-0=28 °C delta x=5.92 x 10-2 m using this you can find the power which transfers from the outside to inside where ice is stored. P= 3.322 J s-1=3.322 W now amount of energy required to melt m kg of ice is $$Q=m_{ice}L_f$$ mice=2 kg ; Lf=3.35 × 105 J kg-1 so we get Q= 6.7 x 105 J if t is the time required to melt all ice then Q must be equal to P x t . solve for t. its 56 hrs

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